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Vitek1552 [10]
3 years ago
10

What happens when light is scattered? A.it reflects on many different directions. B. It bends as it passes from one medium to an

other. C. It vibrates in only one plane. D. It’s is redirected as it passes through a medium.
Physics
1 answer:
umka2103 [35]3 years ago
5 0

Answer:

A

Explanation:

Scattering of light occurs when light passes through an imperfect medium (such as an ice block filled with bubbles). Each ray of light hit the medium differently and hence deflected differently from the rest. An example of a case scenario is during a hot  dry day on tarmac that causes one to see a 'water pool' on the road due to  mirage.

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Answer:

-24 m/s

Explanation:

mass of the bowling ball =  3 kg

time (t) = 0.3 seconds

Force = 24 N

initial velocity u = ???

We know that;

Force = mass × acceleration (a)

So;

24 = 3 × a

a = 24/3

a = 8 m/s²

Also;

From equation of motion; acceleration is given by the relation;

a =\frac{v-u}{t}

if v = 0

then ;

8 = \frac{0-u}{0.3}

24 = 0- u

u = -24 m/s

Thus; the  initial velocity of the bowling ball when it first touched the mattress =  -24 m/s

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4 years ago
In the equation for the gravitational force between two objects, which quantity must be squared?​
Trava [24]
The distance quantity/ measurement must be squared.
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State the Newton 2nd law of motion and also prove that F= ma<br>​
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3 0
3 years ago
The electric field strength in the space between two closely spaced parallel disks is 1.0 10^5 N/C. This field is the result of
alex41 [277]

To solve this problem it is necessary to apply the concepts related to the capacitance in the disks, the difference of the potential and the load in the disc.

The capacitance can be expressed in terms of the Area, the permeability constant and the diameter:

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Where,

\epsilon_0 = Permeability constant

A = Cross-sectional Area

d = Diameter

Potential difference between the two disks,

V = Ed

Where,

E = Electric field

d = diameter

Q = Charge on the disk equal to \rightarrow Q=ne=(3.9*10^9)(1.6*10^{-19})= 6.24*10^{-10}C

Through the value found and the expression given for capacitance and potential, we can define the electric charge as

Q = CV

Q = \frac{\epsilon A}{d}(Ed)

Q = \epsilon_0 AE

Q = \epsilon_0 \pi(\frac{d}{2})^2E

Q = \frac{\epsilon \pi d^2E}{4}

Re-arranging the equation to find the diameter of the disks, the equation will be:

d = \sqrt{\frac{4D}{\epsilon_0 \pi E}}

Replacing,

d = \sqrt{\frac{4(6.24*10^{-10})}{(8.85*10^{-12})\pi(1*10^{5})}}

d = 0.0299m

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What is the difference between speed and velocity
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