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max2010maxim [7]
3 years ago
11

Explain the process of fractional distillation (include cracking)

Engineering
1 answer:
Grace [21]3 years ago
5 0

Answer:

Explanation:

Fractional distillation is the separation of a mixture into its component parts, or fractions. Chemical compounds are separated by heating them to a temperature at which one or more fractions of the mixture will vaporize. It uses distillation to fractionate

it is the separation of a liquid mixture into fractions differing in boiling point (and hence chemical composition) by means of distillation, typically using a fractionating column.

cracking allows large hydrocarbon molecules to be broken down into smaller, more useful hydrocarbon molecules. Fractions containing large hydrocarbon molecules are heated to vaporise them. They are then either: heated to 600-700°C.

I hope this was helpful

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D I think I would of thought about compressing it first tho

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Remy noticed that after oiling his skateboard wheels, it was easier to reach the speeds he needed to perform tricks. How did the
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Answer:

The oil reduced friction between the moving parts of the skateboard. ( A )

Explanation:

The oil reduced Friction between the moving parts of the skateboard and this is because the reduction in friction between moving parts causes an increase in speed.

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10. True or False: You should select your mechanic before you experience vehicle failure.
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True

Explanation:

Always see a professional if you have any issues that is not in your scope of practice

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What is the maximum value of the bending stress at the critical cross-section?
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Answer:

The bending stress increases linearly away from the neutral axis until the maximum values at the extreme fibers at the top and bottom of the beam. The maximum bending stress is given by: where c is the centroidal distance of the cross section (the distance from the centroid to the extreme fiber).

Explanation:

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8 0
3 years ago
Compressed Air In a piston-cylinder device, 10 gr of air is compressed isentropically. The air is initially at 27 °C and 110 kPa
Helen [10]

Answer:

(a) 2.39 MPa (b) 3.03 kJ (c) 3.035 kJ

Explanation:

Solution

Recall that:

A 10 gr of air is compressed isentropically

The initial air is at = 27 °C, 110 kPa

After compression air is at = a450 °C

For air,  R=287 J/kg.K

cv = 716.5 J/kg.K

y = 1.4

Now,

(a) W efind the pressure on [MPa]

Thus,

T₂/T₁ = (p₂/p₁)^r-1/r

=(450 + 273)/27 + 273) =

=(p₂/110) ^0.4/1.4

p₂ becomes  2390.3 kPa

So, p₂ = 2.39 MPa

(b) For the increase in total internal energy, is given below:

ΔU = mCv (T₂ - T₁)

=(10/100) (716.5) (450 -27)

ΔU =3030 J

ΔU =3.03 kJ

(c) The next step is to find the total work needed in kJ

ΔW = mR ( (T₂ - T₁) / k- 1

(10/100) (287) (450 -27)/1.4 -1

ΔW = 3035 J

Hence, the total work required is = 3.035 kJ

4 0
3 years ago
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