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xeze [42]
3 years ago
13

A golf ball is hit with an initial velocity of 155 ft/s at an angle of 23 degrees with the horizontal. After 1.4 seconds, how fa

r has the golf ball traveled horizontally and vertically?. a. 199.7 feet horizontally and 75.2 feet vertically. b. 60.6 feet horizontally and 168.4 feet vertically. c. 199.7 feet horizontally and 53.4 feet vertically. d. 60.6 feet horizontally and 174.4 feet vertically.
Physics
1 answer:
riadik2000 [5.3K]3 years ago
6 0

<span>2) s(t) = 155tcos(23°) </span>
<span>=> s(1.4) = 155 * 1.4 * cos(23°) </span>
<span>=> s(1.4) ≈ 199.7 ft (1 dp) <=- distance displaced horizontally </span>

<span>a(t) = -32 ft/s^2 </span>
<span>=> v(t) = -32t + 155sin(23°) </span>
<span>=> h(t) = -16t^2 + 155tsin(23°) </span>
<span>=> h(1.4) = -16(1.4)^2 + 155(1.4)sin(23°) </span>
<span>=> h(1.4) ≈ 53.4 ft (1 dp) <== distance displaced vertically.</span>
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Answer:

W = - 118.24 J (negative sign shows that work is done on piston)

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For a transformer, \dfrac{V_1}{V_2}=\dfrac{N_1}{N_2}

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