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xeze [42]
3 years ago
13

A golf ball is hit with an initial velocity of 155 ft/s at an angle of 23 degrees with the horizontal. After 1.4 seconds, how fa

r has the golf ball traveled horizontally and vertically?. a. 199.7 feet horizontally and 75.2 feet vertically. b. 60.6 feet horizontally and 168.4 feet vertically. c. 199.7 feet horizontally and 53.4 feet vertically. d. 60.6 feet horizontally and 174.4 feet vertically.
Physics
1 answer:
riadik2000 [5.3K]3 years ago
6 0

<span>2) s(t) = 155tcos(23°) </span>
<span>=> s(1.4) = 155 * 1.4 * cos(23°) </span>
<span>=> s(1.4) ≈ 199.7 ft (1 dp) <=- distance displaced horizontally </span>

<span>a(t) = -32 ft/s^2 </span>
<span>=> v(t) = -32t + 155sin(23°) </span>
<span>=> h(t) = -16t^2 + 155tsin(23°) </span>
<span>=> h(1.4) = -16(1.4)^2 + 155(1.4)sin(23°) </span>
<span>=> h(1.4) ≈ 53.4 ft (1 dp) <== distance displaced vertically.</span>
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F = m * a

The apple's acceleration is not influenced by the acceleration due to gravity for this question.  In real life it most certainly is influenced by gravity.

F = m * a

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Answer:

Explanation:

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a = 3.79 x 10^14m/s^2

  • From F = ma
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E = ma /q = 9.11 x 10^-31 x 3.79 x 10^14 / 1.6 x 10^-19

E = magnitude of this electric field. = 2156.3N/C

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Will mark the brainliest
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Answer:

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friction = 900N

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total = 4000N

w= mxg = 1000*9.81= 9810N

total = 9810 + 4000 = 13810N

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Answer:

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Explanation:

Let teh speed of plane in still air is vp and the speed of air is va.

Irt travels 2670 km in 3 hours against the wind

So,

vp - va = 2670 / 3 = 890 km/h ..... (1)

It travels 11070 km in 9 hours along the wind.

vp + va = 11070 / 9 = 1230 km/h .... (2)

Adding both the equations

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Thus, the runner moves as fast as 7.07 m/s

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