Question

Ammonia is manufactured in large amounts by the reaction N21g2 + 3 H21g2 ¡ 2 NH31g2 (a) How is the rate of consumption of H2 related to the rate of consumption of N2? (b) How is the rate of formation of NH3 related to the rate of consumption of N2?

Answer 1

Answer:

$\large \boxed{\text{(a) three times; (b) twice}}$

Explanation:

1N₂ + 3H₂ ⟶ 2NH₃

$\text{rate} = -\dfrac{1}{1}\cfrac{\text{d[N _{2} ]}}{\text{d}t}= -\dfrac{1}{3}\dfrac{\text{d[H _{2} ]}}{\text{d}t} = +\dfrac{1}{2}\dfrac{\text{d[NH _{3} ]}}{\text{d}t}$

(a) H₂ vs N₂

$-\dfrac{1}{1}\dfrac{\text{d[N _{2} ]}}{\text{d}t}= -\dfrac{1}{3}\dfrac{\text{d[H _{2} ]}}{\text{d}t}\\\\\dfrac{\text{d[H _{2} ]}}{\text{d}t} = 3\dfrac{\text{d[N _{2} ]}}{\text{d}t}\\\\\text{The rate of consumption of hydrogen is \large \boxed{\textbf{three times}} }\\\text{the rate of consumption of nitrogen.}$

(b) NH₃ vs N₂

$-\dfrac{1}{1}\dfrac{\text{d[N _{2} ]}}{\text{d}t} = +\dfrac{1}{2}\dfrac{\text{d[NH _{3} ]}}{\text{d}t}\\\\\dfrac{\text{d[NH _{3} ]}}{\text{d}t} = -2\dfrac{\text{d[N _{2} ]}}{\text{d}t}\\\text{The rate of formation of ammonia is \large \boxed{\textbf{twice}} }\\\text{the rate of consumption of nitrogen.}$