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butalik [34]
3 years ago
14

This is a chemistry question that i don't know how to do. Need some help

Chemistry
1 answer:
koban [17]3 years ago
5 0
C₀=8.10M
c₁=5.28M
v₀=1.58 L
v₁-?

n=c₀v₀=c₁v₁

v₁=c₀v₀/c₁

v₁=8.10*1.58/5.28=2.42 L 
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An airplane travels 200 km/h in 4 hours going to Zambales. What will be the distance and displacement?
Fofino [41]

Answer:

See explanation

Explanation:

Recall that;

Speed = Distance/time

Distance = Speed * time

Speed = 200 km/h

Time = 4 hours

Distance = 200 km/h * 4 hours = 800 kilometres

Displacement has to do with distance covered in a specified direction, in this case, the direction is towards Zambales.

Hence, the displacement is  800 kilometres towards Zambales.

7 0
3 years ago
How does the concentration of reactants affect the rate of a reaction
Naddika [18.5K]

Answer:

B

Explanation:

If the concentration is increased, there are more particles to collide with each other, increasing the rate of the reaction.

5 0
4 years ago
A mixture is made of 40 ml of salt water to 200 ml of solution. What percent of the solution is salt water?
Serggg [28]

Answer:

16.7%

Explanation:

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5 0
3 years ago
Given the equilibrium constants for the following two reactions at a 298K:NiO(s) + H2(g) ⇌ Ni(s) + H2O(g) Kc=40NiO(s) +CO(g) ⇌ N
shusha [124]

Answer:

The value  is  K_C =  \frac{40}{600}

Explanation:

From the question

   The equation given is  

            NiO(s) + H2(g) ⇌ Ni(s) + H2O(g) Kc=40          (1)

            NiO(s) +CO(g) ⇌ Ni(s) +CO2(g) Kc=600         (2)

Generally the reverse of the second equation as shown below

            Ni(s) +CO2(g) ⇌  NiO(s) + CO(g)                 (3)

The equilibrium constant becomes    K_c  ' =  \frac{1}{600}  

 Now  adding  1  and  3 we obtain

      NiO(s) + H2(g)+ Ni(s) +CO2(g) ⇌ Ni(s) + H2O(g)+NiO(s) + CO(g)        

               CO2(g) + H2(g) ⇌ CO(g) + H2O(g)

Hence the equilibrium constant for the resulting equation is mathematically evaluated as

           K_C =  K_c' *  K_c

=>       K_C =  \frac{1}{600}  *  40

=>         K_C =  \frac{40}{600}

       

6 0
3 years ago
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