Answer:
f1 = -3.50 m
Explanation:
For a nearsighted person an object at infinity must be made to appear to be at his far point which is 3.50 m away. The image of an object at infinity must be formed on the same side of the lens as the object.
∴ v = -3.5 m
Using mirror formula,
i/f1 = 1/v + 1/u
Where f1 = focal length of the contact lens, v = image distance = -3.5 m, u = object distance = at infinity(∞) = 1/0
∴ 1/f1 = (1/-3.5) + 1/infinity
Note that, 1/infinity = 1/(1/0) = 0/1 =0.
∴ 1/f1 = 1/(-3.5) + 0
1/f1 = 1/(-3.5)
Solving the equation by finding the inverse of both side of the equation.
∴ f1 = -3.50 m
Therefore a converging lens of focal length f1 = -3.50 m
would be needed by the person to see an object at infinity clearly
Answer:
D) 8
Explanation:
Due to the octet rule the most stable atoms will have 8 valence electrons.
The gravitational force on block B is twice as much as the gravitational force on block A.
<h3>What is Force?</h3>
Force is the product of mass and acceleration. If the mass of A is 1Kg and the mass of B is 2Kg, In order to give the masses the same horizontal acceleration, the magnitude of the force on block B must be twice as much as the force on block A.
Given that the mass of A is 1Kg and the mass of B is 2Kg, the gravitational force on block B is twice as much as the gravitational force on block A.
If I hold block A with a mass of 1 kg in one hand and block B with a mass of 2 kg in the other and release both from the same height above the ground at the same time, the two blocks hit the ground at the same time, because they both accelerate at the same rate while falling. The greater gravitational force on block B is compensated by its greater mass, giving it the same acceleration.
Learn more about force:brainly.com/question/12528243
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Answer:
α = 1.32 rad/s²
Explanation:
given,
diameter of the bicycle = 0.8 m
radius of the bicycle = 0.4 m
initial speed of the bicyclist,u = 0 m/s
final speed of the bicyclist,v = 22 Km/h = 22 x 0.278
= 6.12 m/s
time,t = 11.6 s
acceleration =
=
=0.53 m/s²
we know,
a = α r


α = 1.32 rad/s²
the angular acceleration of the wheels is equal to α = 1.32 rad/s²