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Anton [14]
3 years ago
9

What is tan θ for the given triangle?

Physics
2 answers:
yulyashka [42]3 years ago
7 0
Tan = opposite/adjacent
= 20/15
=4/3
Nuetrik [128]3 years ago
4 0

Answer:

it's C

Explanation: 4/3=1.33

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The vertical motion of mass A is defined by the relation x 5 10 sin 2t 1 15 cos 2t 1 100, where x and t are expressed in millime
nikklg [1K]

Explanation:

Given that,

The vertical motion of mass A is defined by the relation as :

x=10\ sin2t+15\ cos2t+100

At t = 1 s

x=10\ sin2+15\ cos2+100

x = 115.33 mm

(a) We know that,

Velocity, v=\dfrac{dx}{dt}

v=\dfrac{d(10\ sin2t+15\ cos2t+100)}{dt}

v=20\ cos2t-30\ sin2t

At t = 1 s

v=20\ cos2-30\ sin2

v = 18.94 mm/s

We know that,

Acceleration, a=\dfrac{dv}{dt}

a=\dfrac{d(20\ cos2-30\ sin2)}{dt}

a=-40\ cos2t-60\ cos2t

At t = 1 s

v=-40\ cos2-60\ cos2

a=-99.93\ mm/s^2

(b) For maximum velocity, \dfrac{dv}{dt}=a=0

-40\ cos2t-60\ cos2t=0

t = 45 seconds

For maximum acceleration, \dfrac{da}{dt}=0

80\ sin2t+120\ cos2t=0

t = 61.8 seconds

Hence, this is the required solution.

5 0
4 years ago
PLEASE HELP!!! !) POINTS WILL BE AWARDED AND BRAINIEST ANSWER IF ITS CORRECT!
Archy [21]
A. Their displacement is the same, zero miles.
7 0
3 years ago
Read 2 more answers
Why is a frame of reference important for describing<br> motion?
stepladder [879]

Answer:

the  frame of reference requires deciding where the object's initial position is and which direction will be considered positive.

Explanation:

4 0
3 years ago
A projectile of mass 6.8 kg kg is shot horizontally with an initial speed of 14.5 m/s from a height of 26.7 m above a flat deser
sleet_krkn [62]

Answer:

Explanation:

Given

mass of projectile m=6.8\ kg

initial horizontal speed u_x=14.5\ m/s

height h=26.7\ m

Considering vertical motion

velocity gained by projectile during 26.7 m motion

v^2-u^2=2 as

v=final velocity

u=initial velocity

a=acceleration

s=displacement

v^2-(0)^2=2\times (9.8)\times (26.7)

v=\sqrt{523.32}

v=22.87\ m/s

Horizontal velocity will remain same as there is no acceleration

final velocity v_{net}=\sqrt{(v)^2+(u_x)^2}

v_{net}=\sqrt{733.57}=27.08\ m/s

Initial kinetic Energy K_i=\frac{1}{2}mu_x^2

K_i=\frac{1}{2}\times 6.8\times (14.5)^2=714.85\ J

Final Kinetic Energy K_f=\frac{1}{2}mv_{net}^2

K_f=\frac{1}{2}\times 6.8\times (27.08)^2

K_f=2493.30\ J

Work done by all the force is equal to change in kinetic Energy of object

Work done by gravity is W_g

W_g=\Delta K

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8 0
3 years ago
Which types of light are not absorbed by the genetic material
ValentinkaMS [17]

Answer:

I know only one type of light that is absorbed by genetic materail and that is UV light

Explanation:

7 0
3 years ago
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