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mrs_skeptik [129]
3 years ago
12

The Ksp of barium sulfate (BaSO4) is 1.1 × 10–10. What is the solubility concentration of sulfate ions in a saturated solution a

t 25°C?
a.1.0 x 10^-5m
b. 1.5 x10^-5m
c. 5.5 x 10^-11m
d.7.4 x 10^-6m
Chemistry
2 answers:
vlada-n [284]3 years ago
6 0
Each mole of barium sulfate releases equal moles of barium ions and sulfate ions. Let the concentration of one substance be x. Thus: 
Ksp = [Ba⁺²][SO₄⁻²]
1.1 x 10⁻¹⁰ = (x)(x)
x = 1.05 x 10⁻⁵

The answer is A.

ch4aika [34]3 years ago
6 0

<u>Given:</u>

Ksp of BaSO4 = 1.1 * 10⁻¹⁰

<u>To determine:</u>

The solubility concentration of SO4²⁻ ions

<u>Explanation:</u>

BaSO4 ↔ Ba²⁺(aq) + SO4²⁻(aq)

Ksp = [Ba²⁺][SO4²⁻]

if 's' is the solubility of the ions then we have

Ksp = s²

s = √ksp = √1.1*10⁻¹⁰ = 1.05*10⁻⁵M

Ans: solubility of sulfate ions is 1.05*10⁻⁵ M

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</span><span>1 mole of HCl = 36,5 g
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</u><span> ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
</span><span>next question.
</span><span>
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</span>
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Read 2 more answers
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