Question

A gas sample in a closed, expandable container of initial volume 5.00 L was allowed to warm from 25°C to 35°C. What was its new volume?

Answer 1

Answer : The new volume of was, 5.17 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=5.00L\\T_1=25^oC=(25+273)K=298K\\V_2=?\\T_2=35^oC=(35+273)K=308K$

Putting values in above equation, we get:

$\frac{5.00L}{298K}=\frac{V_2}{308K}\\\\V_2=5.17L$

Therefore, the new volume of was, 5.17 L