Question

A parachute on a racing dragster opens and changes speed of the car from 85 m/s to 45 m/s in a period of 4.5 seconds. What is the acceleration of the dragster

Answer 1

Answer:

$a=-8.89\ m/s^2$

Explanation:

Initial velocity, u = 85 m/s

Final velocity, v = 45 m/s

Time, t = 4.5 s

We need to find the acceleration of the dragster. The rate at which the velocity of an object changes is called the acceleration of an object. It can be given by :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{45-85}{4.5}\\\\a=-8.89\ m/s^2$

So, the acceleration of the dragster is $8.89\ m/s^2$ and it is deaccelerating.