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Jlenok [28]
4 years ago
11

When Earth pulls on an object, that object also pulls on Earth. The values of these two forces are . This phenomenon can be expl

ained using Newton’s law. We see the object move but not Earth because there’s a difference in their .
Physics
2 answers:
Verizon [17]4 years ago
6 0

Answer:

When Earth pulls on an object, that object also pulls on Earth. The values of these two forces are [the same]. This phenomenon can be explained using Newton’s [third] law. We see the object move but not Earth because there’s a difference in their [mass].

Explanation:

According to Newton’s third law, Earth pulls the object with the same amount of force that the object pulls Earth. The forces act in opposite directions. If there’s a large difference in mass between Earth and the object, the object moves, but Earth doesn’t.

algol134 years ago
5 0
The values of these two forces are equal. Your weight on Earth is equal to the Earth's weight on you. When you and the Earth fall toward each other, your acceleration is greater than the Earth's acceleration, because your mass is less than the Earth's mass.
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A chain reaction results when a uranium atom is struck by a/an ______________released by a nearby Uranium atom undergoing fissio
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8 0
4 years ago
A home uses ten 100-watt lightbulbs for five hours per day. Approximately how many kilowatt-hours of electrical energy are consu
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The electrical energy consumed in one year by using the light bulbs is 8,760 kWh.

The given parameters:

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<h3>What is electrical energy?</h3>

This is the electric power consumed or dissipated at a given period of time.

The  electrical energy consumed in one year by using the light bulbs is calculated as

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E = (100 \times 10) \times (1 \ yr \times \frac{8760 \ hrs}{1 \ yr} )= 8,760,000 \ W att-hours\\\\&#10;E = \frac{8,760,000 }{1000} = 8,760 \ kWh

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2 years ago
What the opposite of suspension physical science physical science
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3 years ago
In the Bohr model of the hydrogen atom, an electron({rm mass};m=9.1; times 10^{ - 31;}{rm kg}) orbits a proton at a distance of
max2010maxim [7]

Answer:

n=6.56×10¹⁵Hz

Explanation:

Given Data

Mass=9.1×10⁻³¹ kg

Radius distance=5.3×10⁻¹¹m

Electric Force=8.2×10⁻⁸N

To find

Revolutions per second

Solution

Let F be the force of attraction

let n  be the number of revolutions per sec made by the electron around the nucleus then the centripetal force is given by

F=mω²r......................where ω=2π  n

F=m4π²n²r...............eq(i)

as the values given where

Mass=9.1×10⁻³¹ kg

Radius distance=5.3×10⁻¹¹m

Electric Force=8.2×10⁻⁸N

we have to find n from eq(i)

n²=F/(m4π²r)

n^{2} =\frac{8.2*10^{-8} }{9.11*10^{-31}* 4\pi^{2} *5.3*10^{-11}  }\\ n^{2}=4.31*10^{31}\\ n=\sqrt{4.31*10^{31}}\\ n=6.56*10^{15}Hz

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Aerogenerators are used to produce electricity from
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