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Jlenok [28]
4 years ago
11

When Earth pulls on an object, that object also pulls on Earth. The values of these two forces are . This phenomenon can be expl

ained using Newton’s law. We see the object move but not Earth because there’s a difference in their .
Physics
2 answers:
Verizon [17]4 years ago
6 0

Answer:

When Earth pulls on an object, that object also pulls on Earth. The values of these two forces are [the same]. This phenomenon can be explained using Newton’s [third] law. We see the object move but not Earth because there’s a difference in their [mass].

Explanation:

According to Newton’s third law, Earth pulls the object with the same amount of force that the object pulls Earth. The forces act in opposite directions. If there’s a large difference in mass between Earth and the object, the object moves, but Earth doesn’t.

algol134 years ago
5 0
The values of these two forces are equal. Your weight on Earth is equal to the Earth's weight on you. When you and the Earth fall toward each other, your acceleration is greater than the Earth's acceleration, because your mass is less than the Earth's mass.
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You drop a ball from a height of 2.0 m, and it bounces back to a height of 1.5 m. a) What fraction of its initial energy is lost
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The fraction of energy that is lost is 25%, it depends how fast the ball was going until it lost 25% of its energy, the gravitational energy was transferred into the kinetic energy that helped the ball bounce back
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Nata [24]

Answer:

Point number 3.

Explanation:

Volcanism can be studied to found out evidence of the internal structure of the Earth.

6 0
2 years ago
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In a fission experiment observed by Hahn and Strassman, uranium-235 was bombarded by neutrons. The products of this ission react
wlad13 [49]

Answer:

helium-4 (90%) or tritium (7%).

Explanation:

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7 0
4 years ago
A robot is on the surface of Mars. The angle of depression from a camera in the robot to a rock on the surface of Mars is 13.69
ra1l [238]

Answer:

The distance between the camera and the rock is 836.6 cm

Explanation:

A right triangle is formed where the hypotenuse (h) is the distance between the rock and the camera. One of the leg (l) is the distance between the camera and the surface. The angle between the hypotenuse and this leg is α = 90° - 13.69° = 76.31°. By definition:

cos α = adjacent/hypotenuse

cos(76.31) = 198.0/h

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3 0
4 years ago
6. A 2-kg ball B is traveling around in a circle of radius r1 = 1 m with a speed (vB)1 = 2 m/s. If the attached cord is pulled d
kipiarov [429]

Answer:

Explanation:

Given that,

Mass of ball m = 2kg

Ball traveling a radius of r1= 1m.

Speed of ball is Vb = 2m/s

Attached cord pulled down at a speed of Vr = 0.5m/s

Final speed V = 4m/s

Let find the transverse component of the final speed using

V² = Vr²+ Vθ²

4² = 0.5² + Vθ²

Vθ² = 4²—0.5²

Vθ² = 15.75

Vθ =√15.75

Vθ = 3.97 m/s.

Using the conservation of angular momentum,

(HA)1 = (HA)2

Mb • Vb • r1 = Mb • Vθ • r2

Mb cancels out

Vb • r1 = Vθ • r2

2 × 1 = 3.97 × r2

r2 = 2/3.97

r2 = 0.504m

The distance r2 to the hole for the ball to reach a maximum speed of 4m/s is 0.504m

The required time,

Using equation of motion

V = ∆r/t

Then,

t = ∆r/Vr

t = (r1—r2) / Vr

t = (1—0.504) / 0.5

t = 0.496/0.5

t = 0.992 second

7 0
3 years ago
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