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Jlenok [28]
3 years ago
11

When Earth pulls on an object, that object also pulls on Earth. The values of these two forces are . This phenomenon can be expl

ained using Newton’s law. We see the object move but not Earth because there’s a difference in their .
Physics
2 answers:
Verizon [17]3 years ago
6 0

Answer:

When Earth pulls on an object, that object also pulls on Earth. The values of these two forces are [the same]. This phenomenon can be explained using Newton’s [third] law. We see the object move but not Earth because there’s a difference in their [mass].

Explanation:

According to Newton’s third law, Earth pulls the object with the same amount of force that the object pulls Earth. The forces act in opposite directions. If there’s a large difference in mass between Earth and the object, the object moves, but Earth doesn’t.

algol133 years ago
5 0
The values of these two forces are equal. Your weight on Earth is equal to the Earth's weight on you. When you and the Earth fall toward each other, your acceleration is greater than the Earth's acceleration, because your mass is less than the Earth's mass.
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The diagram shows the Earth rotating on it's axis. The two stars show different locations on the surface... How long does it tak
amid [387]
My guess would be about 10 years because stars are hot balls of light that are reflections from years ago so it would most likely take awhile
6 0
2 years ago
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Determine the CM of a rod assuming its linear mass density λ (its mass per unit length) varies linearly from λ = λ0 at the left
Dahasolnce [82]

Answer:

x_c= \dfrac{5}{9}L

I=\dfrac {7}{12}\lambda_ 0 L^3

Explanation:

Here mass density of rod is varying so we have to use the concept of integration to find mass and location of center of mass.

At any  distance x from point A mass density

\lambda =\lambda_0+ \dfrac{2\lambda _o-\lambda _o}{L}x

\lambda =\lambda_0+ \dfrac{\lambda _o}{L}x

Lets take element mass at distance x

dm =λ dx

mass moment of inertia

dI=\lambda x^2dx

So total moment of inertia

I=\int_{0}^{L}\lambda x^2dx

By putting the values

I=\int_{0}^{L}\lambda_ ox+ \dfrac{\lambda _o}{L}x^3 dx

By integrating above we can find that

I=\dfrac {7}{12}\lambda_ 0 L^3

Now to find location of center mass

x_c = \dfrac{\int xdm}{dm}

x_c = \dfrac{\int_{0}^{L} \lambda_ 0(1+\dfrac{x}{L})xdx}{\int_{0}^{L} \lambda_0(1+\dfrac{x}{L})}

Now by integrating the above

x_c=\dfrac{\dfrac{L^2}{2}+\dfrac{L^3}{3L}}{L+\dfrac{L^2}{2L}}

x_c= \dfrac{5}{9}L

So mass moment of inertia I=\dfrac {7}{12}\lambda_ 0 L^3 and location of center of mass  x_c= \dfrac{5}{9}L

8 0
3 years ago
Two neutral metal spheres on wood stands are touching. A negatively charged rod is held directly above the top of the left spher
FrozenT [24]

Answer: Option (C) is the correct answer.

Explanation:

As we know that metals are able to conduct electricity so, when a negatively charges rod is kept closer to the left sphere then electrons will enter the sphere.

Since, like charges repel each other. Hence, some of the negative changes from the rod will repel the negative charges of left sphere.

As both left and right spheres are touching each other so, the electrons will move towards the right sphere. As a result, there will be too many electrons (negative charge) present on the right sphere and very less electrons present in the left sphere.

Thus, we can conclude that the statement right sphere is negatively charged, another is charged positively, is true.

7 0
3 years ago
Read 2 more answers
How much will the kinetic energy of a school bus increase if its velocity is tripled?
son4ous [18]

Answer:

Explanation:

Given a school bus.

Let say initially the school bus is traveling with speed "v"

Let assume mass of school bus is "m"

Then, the initial kinetic energy is

K.E_initial = ½mv²

Now, if the initial velocity is tripled,

Then, the new velocity is

v_new = 3v.

Note: the mass of the school does not change it is constant

Then, new kinetic energy is

K.E_new = ½m(v_new)²

v_new = 3v

Then,

K.E_new = ½m(3v)²

K.E_new = ½m × 9v²

K.E_new = 9 × ½mv²

Since K.E = ½mv²

Then,

K.E_new = 9 × K.E

So, the new kinetic energy will be 9 times the initial kinetic energy.

So, option D is correct

D. It will be nine times greater.

4 0
3 years ago
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likoan [24]

Answer:

911700\ \text{Pa}

Explanation:

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V_1 = Initial volume

V_2= Final volume = \dfrac{V_1}{9}\\\Rightarrow \dfrac{V_1}{V_2}=9

Temperature is the same in the initial and final state

From the ideal gas law we have

P_1V_1=P_2V_2\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=P_1\times9\\\Rightarrow P_2=1.013\times 10^5\times 9\\\Rightarrow P_2=911700\ \text{Pa}

The final pressure of the system is 911700\ \text{Pa}.

5 0
3 years ago
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