Question

A uniform electric field of magnitude 365 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. The electron has moved 3.00 cm. (a) What is the work done by the field on the electron?

Answer 1

Answer:

$W= 1.752\times10^\left ( -18\right )$ $Joules$

Explanation:

given E= 365 N/C in positive x-direction

electron initially at rest q=  1.6$\times10^{-19}$C

force experienced by the electron F= Eq

⇒F= 365$\times1.6\times10^{-19}$

=584$\times10^{-19}$

Distance traveled by electron S = 3 cm

now work done W= F$\times$S=584$\times$$10^{-19}$$\times3$$\times10^{-2}$

W= 1752$\times10^\left (-21 \right )$ Joules

Work done= 1.752$\times10^\left (-18 \right )$ Joules