Answer: 8.43 m
Explanation:
Given
Mass of the rocket, m = 600 g = 0.6 kg
Speed of riling, v = 2.5 m/s
F = mg, where
F = weight of the rocket in N
m = mass of the rocket in kg
g = acceleration due to gravity in m/s²
F = 0.6 * 9.8
F = 5.88 N
Since the the vertical thrust on the rocket is 8 N and 5.88 N of it will be used to counter the rockets weight. Thus, the remaining 2.12 N is what is available to provide acceleration.
Upward acceleration of the rocket is..... F = ma, a = F / m
a = 2.12 / 0.6
a = 3.53 m/s²
using equation of motion, we will calculate how long it will take to rise 20 m in the air
S = ut + 1/2at², where u = 0
20 = 1/2 * 3.53 * t²
t² = 4. / 3.53
t² = 11.33
t = √11.33 = 3.37 s
The distance then is
v = Δx / t, such that
Δx = v * t
Δx = 2.5 * 3.37
Δx = 8.43 m
Explanation:
It is given that,
Angular frequency, 
Maximum displacement, A = 0.5 m at t = 0 s
We need to find the time at which it reaches its maximum speed. Firstly, we will find the maximum velocity of the object that is exhibiting SHM.
............(1)
Acceleration of the object, 
...............(2)
Using first equation of motion we can calculate the time taken to reach maximum speed.
t = 0.25 s
So, the object will take 0.25 seconds to reach its maximum speed. Hence, this is the required solution.
Answer:
yes
Explanation:
kinetic energy is when something has a force acting upon it. potential energy is the opposite
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