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Brut [27]
3 years ago
9

When the reaction:

Physics
1 answer:
Alex787 [66]3 years ago
3 0
The last sentence is a little vague.
However, I will assume that by the last sentence you meant 
Reaction~Rate=[CH_3Cl][H_2O]
The reaction order respective to any substance is the value of the exponent on that substance in the Reaction Rate equation.
We see that the exponent on both the substance is 1 so the reaction order with respect to each substance is 1.
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Need help with a physics question.
Verdich [7]

QUESTION:

WHAT IS THE MAGNITUDE OF THE MAGNETIC FIELD AT RIGHT ANGLES TO THE PROTON'S PATH?

ANSWER:

=<em><u>☑</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><em><u>4</u></em><em><u> </u></em><em><u>T</u></em>

8 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST FILE IS ATTACHED
Ainat [17]

Answer:

chemical, electrical

mechanical, electrical

heat, light

7 0
3 years ago
A mercury thermometer has a glass bulb of interior volume 0.100 cm3 at 10°c. the glass capillary 10) tube above the bulb has an
Nadya [2.5K]
Initial volume of mercury is
V = 0.1 cm³

The temperature rise is 35 - 5 = 30 ⁰C = 30 ⁰K.

Because the coefficient of volume expansion is 1.8x10⁻⁴ 1/K, the change in volume of the mercury is 
ΔV = (1.8x10⁻⁴ 1/K)*(30 ⁰K)(0.1 cm³) = 5.4x10⁻⁴ cm³

The cross sectional area of the tube is
A = 0.012 mm² = (0.012x10⁻² cm²).
Therefore the rise of mercury in the tube is
h = ΔV/A
   = (5.4x10⁻⁴ cm³)/(0.012x10⁻² cm²)
   = 4.5 cm

Answer: 4.5 cm
7 0
3 years ago
Read 2 more answers
Which of the following are equivalent units?
ratelena [41]

Answer:

B is the correct answer

Explanation:

5 0
2 years ago
determine the force of gravitational attraction between a 78kg boy sitting 2 meters away from a 65kg girl.
bixtya [17]

Answer:

F=8.45\times 10^{-8}\ N

Explanation:

Given that,

Mass of a boy is 78 kg

Mass of a girl is 65 kg

We need to find the force of gravitational attraction between them if they are 2 m away.

The formula for the gravitational force is given by :

F=\dfrac{Gm_1m_2}{r^2}\\\\F=\dfrac{6.67\times 10^{-11}\times 78\times 65}{(2)^2}\\\\=8.45\times 10^{-8}\ N

So, the force between them is 8.45\times 10^{-8}\ N.

8 0
2 years ago
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