Answer:
The change in the mechanical energy of the projectile is 43,750 J
Explanation:
Given;
mass of the projectile, m = 5 kg
initial velocity of the projectile, u = 200 m/s
final velocity of the projectile, v = 150 m/s
The change in mechanical energy is calculated from the principle of conservation of energy;
ΔP.E = ΔK.E
The change in potential energy is zero (0)
0 = ΔK.E
ΔK.E = K.E₁ - K.E₂
ΔK.E = ¹/₂mu² - ¹/₂mv²
ΔK.E = ¹/₂m(u² - v²)
ΔK.E = ¹/₂ x 5(200² - 150²)
ΔK.E = 43,750 J
Therefore, the change in the mechanical energy of the projectile is 43,750 J
Very good question, The answer you might be looking for is 7.467m/s^2.
Have a blessed day God bless.
The speed of the wave in water is 833.33 m/s
The given parameters;
- depth of the wrecked ship, d = 1000 m
- frequency of the wave transmitted, f = 50 kHz
- time of motion of the echo, t = 2.4 s
The speed of the wave in water is calculated by applying echo equation as shown below;
Thus, the speed of the wave in water is 833.33 m/s
Learn more here: brainly.com/question/23433611
All ik is that gold is a rare earth metal that dos not conduct electricity
