The answer would be D, negative acceleration
Answer:
Option A
Explanation:
The Equation represents the displacement of the object which is represented by x
so, means when time is zero so we replace t with zero in the equation,
now for v which is velocity we need to differentiate the function as the formula for velocity is rate of change of displacement over time so we derivate the equation once and get,
now for we insert t = 0 and get
now for a which is acceleration the formula of acceleration is rate of change of velocity over time, so we differentiate the the equation of v(velocity) once or the equation of x(displacement) twice so now we get,
so Option A is your answer.
Remember derivative of a constant is always zero because a constant value has no rate of change has its a constant hence the derivative is 0
<h2>
Answer: Toward the center of the circle.</h2>
This situation is characteristic of the uniform circular motion , in which the movement of a body describes a circumference of a given radius with constant speed.
However, in this movement the velocity has a constant magnitude, but its direction varies continuously.
Let's say is the velocity vector, whose direction is perpendicular to the radius of the trajectory, therefore
the acceleration is directed toward the center of the circumference.