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Norma-Jean [14]
3 years ago
7

What do you think will happen by adding cold seawater to "your ocean”

Chemistry
1 answer:
Contact [7]3 years ago
8 0

Answer:

it will be troubled and won't have peace

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What is 2KNO3 + 1H2CO3 = 1K2CO3+2HNO3 reaction type
Tema [17]
DR is the correct answer

hope this helps
4 0
3 years ago
Read the following chemical equation: Ti + 2Cl2 → TiCl4 Which statement best identifies and describes the reducing agent in the
goldenfox [79]

Answer: Ti is the reducing agent because it changes from 0 to +4 oxidation state.

Explanation:

  • Firstly, we need to identify the reducing agent and the oxidizing agent.
  • The reducing agent: is the agent that has been oxidized via losing electrons.
  • The oxidizing agent: is the agent that has been reduced via gaining electrons.
  • Here, Ti losses 4 electrons and its oxidation state is changed from 0 to +4 and Cl₂  gains one electron  and its oxidation state is changed from 0 to -1.
  • So, Ti is the reducing agent because its oxidation state changes from  0 to +4.
  • Cl₂ is the oxidizing agent because its oxidation state changes from 0 to -1.
  • Thus, The right answer is Ti is the reducing agent because it changes from 0 to +4 oxidation state.
4 0
3 years ago
A 16.0 16.0 L sample of neon gas has a pressure of 23.0 23.0 atm at a certain temperature. At the same temperature, what volume
Otrada [13]

Answer: 245 L

Explanation:-

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=23.0atm\\V_1=16.0L\\P_2=1.50atm\\V_2=?

Putting values in above equation, we get:

23.0\times 16.0=1.50\times V_2\\\\V_2=245L

Thus new volume of gas is 245 L

3 0
3 years ago
An unkown element has been found to occur in two different stable isotopes. One isotope has an abundance of 57.21 percent and ha
NeX [460]

Answer: 121.7558 amu

Explanation:

Average atomic mass of the unknown element =

(Mass of isotope 1 x Relative Abundance of Isotope 1) + ( Mass of Isotope 2 x Relative Abundance of Isotope 2)

(120.9 x 0.5721) + (122.9 x 0.4279) = 69.16689 + 52.58891

Average mass of the unknown element = 121.7558 amu

6 0
3 years ago
When a checmical eeaction occurs,______________
irinina [24]
<span>when two or more molecules interact and the molecules change.</span>
4 0
3 years ago
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