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Norma-Jean [14]
3 years ago
7

What do you think will happen by adding cold seawater to "your ocean”

Chemistry
1 answer:
Contact [7]3 years ago
8 0

Answer:

it will be troubled and won't have peace

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What is the general formula for the homologous series that includes ethene?
Masja [62]

Answer:

See below

Explanation:

The common formula of the same alkene series is CnH2n, where n is the quantity of atoms of carbon. Owing to the hydrocarbons of alkenes with at least one double carbon relation, the alkene-like sequence starts with ethen C2H4.

<em><u>Hope this helps.</u></em>

8 0
4 years ago
Who was the first person to invent plastic, and what was their purpose for inventing it?
Damm [24]

Answer:

Leo Hendrik Baekeland

Explanation:

Baekeland discovered Bakelite, the first successful plastic, but wanted to make a more better and more heat resistant plastic.

6 0
4 years ago
Find the number of photons of wavelength = 5.49×10−6 m that must be absorbed to melt 1.00 g of ice.
Misha Larkins [42]
First, we determine the energy required to melt one gram of ice. This is given by:

Energy = mass * latent heat of fusion
Energy = 1 g * 334 J/g
Energy = 334 J

Next, we use Planck's equation which is:

Energy  = number of photons * Planck's constant * speed of light / wavelength

334 = n * 6.64 x 10⁻³⁴ * 3 x 10⁸ / 5.49 x 10⁻⁶
n = 9.20 x 10²¹

9.20 x 10²¹ photons need to be absorbed by the ice.
7 0
3 years ago
PLEASE HELP PLEASE HELP!!
eimsori [14]

Answer:

a) positive feedback

Explanation:

positive as in increasing

5 0
4 years ago
Read 2 more answers
1. Calculate how many moles of glycine are in a 130.0-g sample of glycine.2. Calculate the percent nitrogen by mass in glycine.
Alexxx [7]

Answer:

n=1.732mol

\% N=18.7\%

Explanation:

Hello!

In this case, since the molecular formula of glycine is C₂H₅NO₂, we realize that the molar mass is 75.07 g/mol; thus, the moles in 130.0 g of glycine are:

n=130.0g*\frac{1mol}{75.07 g}\\\\ n=1.732mol

Furthermore, we can notice 75.07 grams of glycine contains 14.01 grams of nitrogen; thus, the percent nitrogen turns out:

\% N=\frac{14.01}{75.07}*100\% \\\\\% N=18.7\%

Best regards!

4 0
3 years ago
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