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3 years ago

A person is just as likely to become dehydrated in the cold as in the heat

2 answers:

8 0

Yes this is true as in cold conditions our body doesn't feel the urge of water therefore we may become dehydrated not even knowing about it and of course in hot coditions we sweat therefore we loose water.
Hope this helps :).

zzz [600]3 years ago

6 0

Explanation:

During winters, due to the cold weather intake of water by human beings is very less as compared to the intake during summer. Also, the intake small amount of water flushes out of the body in the form of urine.

As a result, our body gets dehydrated.

Whereas during summer's, intake of water is more and this water flushes out of the body in the form of sweat. As a result, we feel dehydrated and drink water again and again within some intervals.

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The half life of radon-222 is 3.8 days. How Much of a 100g sample is left after 15.2 days

professor190 [17]

Answer:

6.2 g

Explanation:

In a first-order decay, the formula for the amount remaining after n half-lives is

$N = \frac{N_{0}}{2^{n}}$

where

N₀ and N are the initial and final amounts of the substance

1. Calculate the number of half-lives.

If $t_{\frac{1}{2}} = \text{3.8 da}$

$n = \frac{t}{t_{\frac{1}{2}}} = \frac{\text{15.2 da}}{\text{3.8 da}}= \text{4.0}$

2. Calculate the final mass of the substance.

$\text{N} = \frac{\text{100 g}}{2^{4.0}} = \frac{\text{100 g}}{16} = \text{6.2 g}$

4 0

3 years ago

Fermeroben heres the messages COUGH

lord [1]

I completely understand your gripe. I also believe that you are the better option. It will only take time until she is yours, despite your parent's views. Keep it up

6 0

3 years ago

Give regents and mechanism

Kryger [21]

Answer:

Reagents: 1) $BH_3$ 2) $H_2_O2$ , $OH^-$

Mechanism: Hydroboration

Explanation:

In this case, we have a hydration of alkenes reaction. But, in this example, we have an anti-Markovnikov reaction. In other words, the "OH" is added in the least substituted carbon. Therefore we have to choose an anti-Markovnikov reaction: "hydroboration".

The first step of this reaction is the addition of borane ( $BH_3$ ) to the double bond. Then in the second step, we have the deprotonation of the hydrogen peroxide, to obtain the peroxide anion. In the third step, the peroxide anion attacks the molecule produced in the first step to produce a complex compound in which we have a bond " $BH_2-O-OH$ ". In step number 4 we have the migration of the C-B bond to oxygen. Then in step number 5, we have the attack of $OH^-$ on the $O-BH_2$ to produce an alkoxide. Finally, the water molecule produce in step 2 will protonate the molecule to produce the alcohol.

See figure 1

I hope it helps!

4 0

3 years ago

What percentage of known species are invertebrates?

ehidna [41]

95 percent of species known are invertebrates

6 0

3 years ago

Ill give brainliest if you answer right

Paraphin [41]

Answer:

It'll be the same as 58.44 amu. This is because of the law of conservation of mass which states that total mass of reactants is always equal to the total mass of products formed.

pls give brainliest for the answer

3 0

2 years ago

Read 2 more answers