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natita [175]
4 years ago
6

What is the purpose of repeating a measurement using a different method

Physics
1 answer:
Dimas [21]4 years ago
7 0
I dunno, I guess to see if you could get a different answer
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____________ are used to calculate the distance a continent has moved in a year. a. Space satellites c. Laser beams b. Mirrors d
Law Incorporation [45]
<span> Space satellites, laser beams, mirrors</span> are used to calculate the distance a continent has moved in a year.

Therefore, your correct answer would be "all of the above".
4 0
3 years ago
Two 2.0-mm diameter beads, C and D, are 12mm mm apart, measured between their centers. Bead C has mass 1.0 g and charge 2.5nC nC
Artist 52 [7]

Answer:

d

Explanation:

7 0
3 years ago
You have a stopped pipe of adjustable length close to a taut 62.0 cmcm, 7.25 gg wire under a tension of 4710 NN. You want to adj
Oksana_A [137]

Answer:

6 cm long

Explanation:

F = 4110N

Vo(speed of sound) = 344m/s

Mass = 7.25g = 0.00725kg

L = 62.0cm = 0.62m

Speed of a wave in string is

V = √(F / μ)

V = speed of the wave

F = force of tension acting on the string

μ = mass per unit density

F(n) = n (v / 2L)

L = string length

μ = mass / length

μ = 0.00725 / 0.62

μ = 0.0116 ≅ 0.0117kg/m

V = √(F / μ)

V = √(4110 / 0.0117)

v = 592.69m/s

Second overtone n = 3 since it's the third harmonic

F(n) = n * (v / 2L)

F₃ = 3 * [592.69 / (2 * 0.62)

F₃ = 1778.07 / 1.24 = 1433.927Hz

The frequency for standing wave in a stopped pipe

f = n (v / 4L)

Since it's the first fundamental, n = 1

1433.93 = 344 / 4L

4L = 344 / 1433.93

4L = 0.2399

L = 0.0599

L = 0.06cm

L = 6cm

The pipe should be 6 cm long

6 0
3 years ago
A sound wave travels twice as far in neon (Ne) as it does it krypton (Kr) in the same time interval. Both neon and krypton can b
avanturin [10]

Answer:

281.6 K

Explanation:

The speed of sound in an ideal gas is given by c = √(γKT/m).

From the question speed of sound in Ne, c₁ = 2c₂ speed of sound in Kr

c₁ = √(γKT₁/m₁) and c₂ = √(γKT₂/m₂)

So  √(γKT₁/m₁)  = 2√(γKT₂/m₂) where T₁, m₁ and T₂, m₂ are the temperatures and atomic masses of Neon and Krypton respectively.

So, √(T₁/m₁)  = 2√(T₂/m₂)

(T₁/m₁)  = 4(T₂/m₂) (squaring both sides)

T₁ = 4(T₂m₁/m₂)

Given that m₁ = 20.2 u , m₂ = 83.8 u, T₂ = 292 K

T₁ = 4(292 × 20.2/83.8) K = 23593.6/83.8 = 281.55 K ≅ 281.6 K

6 0
3 years ago
Which type of mirror always has an image that is smaller than the object?
BaLLatris [955]

Which type of mirror always has an image that is smaller than the object?

convex

7 0
3 years ago
Read 2 more answers
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