Answer:
I believe it is 1/6 M
Explanation:
sorry if i am not right but i think i am
Answer:
Explanation:
Let mass and velocity of proton be m and v .
1/2 m v² = 59 x 10⁶ e V
= 59 x 10⁶ x 1.6 x 10⁻¹⁹ J
= 94.4 x 10⁻¹³ J
mv² = 188.8 x 10⁻¹³ J
v² = 188.8 x 10⁻¹³ / m
= 188.8 x 10⁻¹³ / 1.67262 x 10⁻²⁷
= 112.8768 x 10¹⁴
v = 10.62 x 10⁷ m / s
In circular path of proton , magnetic force equals centripetal force .
m v² / r = B q v , B is magnetic field , q is charge on proton , r is radius of circular path .
188.8 x 10⁻¹³ / 5.8 x 10¹⁰ = B x 1.6 x 10⁻¹⁹ x 10.62 x 10⁷
B = 1.9157 x 10⁻¹¹ T.
3.3 x10^4N/m²
6.7 x105N/m²
Explanation:
Let the young modulus of the relaxed biceps be
Y= F¹Lo/ deta L1 x A
= 25 x0.2/ 0.03* 50cm²(1m²
0.0004cm^-²)
= 3.3x10^4N/m²
But young modules of muscle under maximum tension will be
Y= F"Lo/ deta L" x A
= 500x 0.2/ 0.03* 50cm²(1m²
0.0004cm^-²)
= 6.7 x10^5N/m²
Thrust - Friction = mass * acceleration
Friction = coefficient * mass * gravity
Friction = 0.10 * 75 * 9.8 = 73.5 N
Substituting:
200N - 73.5 = 75a
a = 1.69 m/s^2
Obtaining final velocity at the end of 41 seconds:
Vf = at
Vf = 1.69 (41)
Vf = 69.15 m/s
Using the formula for displacement for linear motion problems:
s = Vo*t + (1/2)a*t^2
s = 0 + (1/2)(1.69)(41^2)
s = 1420.445 meters
After he runs out of fuel, we use the following formula to find the distance that he coasts:
F = ma = coefficient*m*g
a = 0.10(9.8)
a = -0.98
Vf^2 = Vo^2 + 2as
0 = 69.15^2 + 2(-0.98)s
s = 2439. 65
Adding the 2 displacements together to obtain the total distance:
Total distance = 2439.65 + <span>1420.45 meters
Total distance = 3860.1 meters</span>