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3 years ago

How does a shovel make work easier for digging a hole?

2 answers:

6 0

A shovel makes work easier when digging a hole because it can gather a large amount of dirt in a short period of time. Also, shovels are very strong so they can break through roots and other objects in the ground to make a hole. Hope I helped!!! :)

bezimeni [28]3 years ago

4 0

It makes it easier to dig a hole because it helps pick up dirt

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An unknown material has a mass

atroni [7]

Answer: 1896.55J/kg°C

Explanation:

The quantity of Heat Energy (Q) required to heat a material depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 1320 joules

Mass of material = 5.61kg

C = ? (let unknown value be Z)

Φ = 0.124°C

Then, Q = MCΦ

1320J = 5.61kg x Z x 0.124°C

1320J = 0.696kg°C x Z

Z = (1320J / 0.696kg°C)

Z = 1896.55 J/kg°C

Thus, the specific heat of the material is 1896.55J/kg°C

4 0

3 years ago

Read 2 more answers

Question number 8 Plz help

Dennis_Churaev [7]

To me, that sounds like the "Law of Conservation of Energy".

5 0

3 years ago

A man on a bicycle of total mass of 10kg has a Velocity of 2 ms.' He Paddles faster for 5 seconds and the velocity Increase to i

sesenic [268]

Answer:

the value of force, F=4.0N

Explanation:

Firstly, recall velocity-time equation

v=u+at
(4)=(2)+a(5)
a=0.4m/s²

Secondly, recall the Newton's 2nd Law

F=ma
F=(10)(0.4)
F=4.0N

7 0

2 years ago

Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is

anastassius [24]

The car A has a mass of 1200 kg.

The car B has the mass of 1900 kg.

It is given that velocity of car A is given as 22 Km/hr

The car B has the velocity of 25 Km/hr.

Let the mass of two bodies are denoted as $m_{1} \ and\ m_{2}$

Let the velocity of cars A and B are denoted as $v_{1} \ and\ v_{2}$

The momentum before collision is-

$p_{i} =m_{1} v_{1} +m_{2} v_{2}$

[Here p stand for momentum.]

We are asked to calculate the final momentum of the system after collision.

The answer of the question is based law of conservation of linear momentum.

As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

Let after the collision the velocity of A and B are $v'_{1} \ and\ v'_{2}$

Hence the final momentum of the system is-

$p_{f} = m_{1} v'_{1} +m_{2} v'_{2}$

As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e

$p_{i} =p_{f}$

$m_{1} v_{1} +m_{2}v_{2} =m_{1} v'_{1} +m_{2} v'_{2}$

Hence the option A is right.

7 0

3 years ago

Read 2 more answers

can someone describe how someone is moving-- have examples of positive velocity negative velocity and acceleration and the perso

Rama09 [41]

Assume the motion when you are in the car or in the school bus to go to the school.

To describe the motion the first thing you need is a point of reference. Assume this is your house.

This should be a description:

When you are sitting and the car has not started to move you are at rest.

The car starts moving from rest, gaining speed, accelerating. You start to move away from your house, with a positive velocity (from you house to your school) and positive acceleration (velocity increases).

The car reaches a limit speed of 40mph, and then moves at constant speed. The motion is uniform, the velocity is constant, positive, since you move in the same direction), and the acceleration is zero.

When the car approaches the school, the driver starts to slow down. Then, you speed is lower but yet the velocity is positive, as you are going in the same direction. The acceleration is negative because it is in the opposite direction of the motion.

When the car stops, you are again at rest: zero velocity and zero acceleration.

In all the path your velocity was positive, constant at times (zero acceleration) and variable at others (accelerating or decelerating).

When you comeback home, then you can start to compute negative velocities, as you will be decreasing the distance from your point of reference (your house).

4 0

3 years ago