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4 years ago

When a scale goes by so fast we almost can't hear the individual notes, it's called

Physics

2 answers:

atroni [7]4 years ago

6 0

It's called d. a glissando (glissando means "to slide" - which is how you play one)

Fofino [41]4 years ago

4 0

Answer:

(d) A glissando

Explanation:

Glissando :

A fast rising or plummeting of the scale. In the event that a glissando is performed on a piano or harp, only one out of every odd semitone is played, in light of the fact that the finger is drawn crosswise over just the white keys on account of the piano, or the scale accessible on account of the harp. Assuming, be that as it may, a glissando is performed on a stringed instrument, for example, a violin, every semitone would be sounded as the finger is either slid up or down the length of a string, or fingering each note independently. A glissando is additionally conceivable on wind instruments, be that as it may, each note must be fingered independently with the striking exemption of the trombone.Due to the special development of the trombone without any valves or keys, the glissando is anything but difficult to perform.

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A high-jumper, having just cleared the bar, lands on an air mattress and comes to rest. Had she landed directly on the hard grou

Hoochie [10]

Answer:

e. the air mattress exerts the same impulse, but a smaller net avg force, on the high-jumper than hard-ground.

Explanation:

This is according to the Newton's second law and energy conservation that the force exerted by the hard-ground is more than the force exerted by the mattress.

The hard ground stops the moving mass by its sudden reaction in the opposite direction of impact force whereas the mattress takes a longer time to stop the motion of same mass in a longer time leading to lesser average reaction force.

<u>Mathematical expression for the Newton's second law of motion is given as:</u>

$F=\frac{dp}{dt}$ ............................................(1)

where:

dp = change in momentum

dt = time taken to change the momentum

We know, momentum:

$p=m.v$

Now, equation (1) becomes:

$F=\frac{d(m.v)}{dt}$

<em>∵mass is constant at speeds v << c (speed of light)</em>

$\therefore F=m.\frac{dv}{dt}$

and, $\frac{dv}{dt} =a$

where: a = acceleration

$\Rightarrow F=m.a$

also

$F\propto \frac{1}{dt}$

so, more the time, lesser the force.

<em>& </em><u><em>Impulse:</em></u>

$I=F.dt$

$I=m.a.dt$

$I=m.\frac{dv}{dt}.dt$

$I=m.dv=dp$

∵Initial velocity and final velocity(=0), of a certain mass is same irrespective of the stopping method.

So, the impulse in both the cases will be same.

4 0

3 years ago

How sunlight is converted into potential energy by plants

lozanna [386]

Sunlight is radiant energy. The radiant energy is converted into chemical energy through the process of photosynthesis in the chlorophyll i think thats what u looking for

7 0

3 years ago

A. What is the coefficient of kinetic friction?

Andrews [41]

Explanation:

Coefficient of kinetic friction is the resistive force that opposes the motion of a body as it moves and is in contact with another body.

It is found by dividing the frictional force by the normal force.

Friction is a force that opposes motion.
Static friction is for bodies that are not in motion
Kinetic friction is for moving bodies.

7 0

3 years ago

I need help with the second one asap

dangina [55]

Answer:

what I don't know show a question mark me as brainleast

6 0

3 years ago

Read 2 more answers

Particles q1, 92, and q3 are in a straight line.

NNADVOKAT [17]

The net force on q₃ will be 17.51 N. The net force is the algebraic sum of the two forces on the pleading q₃

<h3 /><h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The force,by the charge q₁ on the q₃;

$\rm F_{31}} = \frac{Kq_1q_3}{r^2} \\\\ \rm F_{31}} = \frac{9 \times 10^9 \times -28.1 \times 10^{-6}\times \times -47.9 \times 10^{-6}}{(0.600)^2} \\\\ F_{31}} =33.64 \ N$

The force,by the charge q₂ on the q₃;

$\rm F_{32}} = \frac{Kq_2q_3}{r^2} \\\\ \rm F_{32}} = \frac{9 \times 10^9 \times 25.5 \times 10^{-6}\times \times -74.9\times 10^{-6}}{(0.300)^2} \\\\ F_{32}} =-19.09 \ N$

The net force is the sum of the two forces;

$\rm F_{net}=F_{32}+F_{31}\\\\\ \rm F_{net}=36.6-19.9 \\\\ \rm F_{net}=17.51 \ N$

Hence, the net force on q₃ will be 17.51 N.

To learn more about Columb's law, refer to the link;

brainly.com/question/1616890

#SPJ1

8 0

3 years ago