A steel rod is pulled in tension with a stress that is less than the yield strength. The modulus of elasticity may be calculated
1 answer:
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Answer:
Force, F = 187.42 N
Explanation:
It is given that,
Mass of boy, m = 30 kg
Acceleration due to gravity,
Radius of curvature of the roller coaster, r = 15 m
Speed of the car, v = 7.3 m/s
The force acting on the boy are force of gravity and the centripetal force. The net force acting on him is as follows :
F = 187.42 N
So, he press against the seat with a force is 187.42 N. Hence, this is the required solution.
Answer:
Acceleration of the bags is 0.861 m/s²
Explanation:
Given:
Mass of the rock, m = 22.5 kg = mass of the food
Slope, Θ = 55.5°
Now, from the figure, we have
T - mgsinΘ = ma ...................(1)
'a' is the acceleration of the mass
where T is the tension
also for the second mass, we have
mg - T = ma
now substituting the value of T from the equation (1) we get
mg - (ma + mgsinΘ) = ma
or
mg(1 - sinΘ) = (m + m)a
or
a =
on substituting the values we get
a =
or
a = 0.861 m/s²
Hence, the acceleration of the bags is 0.861 m/s²
