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Helen [10]
3 years ago
7

If the distance between the levers input force and the fulcrum is 8 cm, and the distance between the fulcrum and the output forc

e is 24 cm, what is the ideal mechanical advantage of the lever?
Physics
1 answer:
ololo11 [35]3 years ago
5 0

Answer:

Ideal mechanical advantage of the lever is 3.

Explanation:

Given that,

The distance between the levers input force and the fulcrum is 8 cm, d_i=8\ cm

The distance between the fulcrum and the output force is 24 cm, d_o=24\ cm

To find,

The ideal mechanical advantage of the lever.

Solution,

The ratio of the distance between the fulcrum and the output force to the distance between the levers input force and the fulcrum is called the ideal mechanical advantage of the lever. It is given by :

m=\dfrac{d_o}{d_i}

m=\dfrac{24}{8}

m = 3

So, the ideal mechanical advantage of the lever is 3.

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Shalnov [3]

Answer:

x ’= 1,735 m,  measured from the far left

Explanation:

For the system to be in equilibrium, the law of rotational equilibrium must be fulfilled.

Let's fix a reference system located at the point of rotation and that the anticlockwise rotations have been positive

             

They tell us that we have a mass (m1) on the left side and another mass (M2) on the right side,

the mass that is at the left end x = 1.2 m measured from the pivot point, the mass of the right side is at a distance x and the weight of the body that is located at the geometric center of the bar

           x_{cm} = 1.2 -1

          x_ {cm} = 0.2 m

          Σ τ = 0

          w₁ 1.2 + mg 0.2 - W₂ x = 0

          x = \frac{m_1 g\ 1.2 \ + m g \ 0.2}{M_2 g}

          x = \frac{m_1 \ 1.2 \ + m \ 0.2 }{M_2}

let's calculate

          x = \frac{2.9 \ 1.2 \ + 4 \ 0.2 }{8.00}2.9 1.2 + 4 0.2 / 8

           

          x = 0.535 m

measured from the pivot point

measured from the far left is

           x’= 1,2 + x

           x'=  1.2 + 0.535

           x ’= 1,735 m

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Explanation:

Hope this helps!

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