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kiruha [24]
3 years ago
9

A gas cylinder at a pressure of 4408 torr contains a mixture of N2, O2, and helium gases. If the partial pressure of N2 gas is 1

520 torr and the partial pressure of helium is 25 torr, what is the partial pressure of O2?
Physics
1 answer:
inessss [21]3 years ago
6 0

Answer:

P subscript 2 = 4408 - 1520 + 25

P subscript 2 = 4408 - 1545

P subscript 2 = 2863 torr

Partial Pressure for O2 = 2863 torr

Explanation:

In order to get the partial pressure for O2, you are expected to sum that of N2 and Helium then subtract it from the pressure of the gas cylinder

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In general, an organism will be more likely to develop phobias of __________.
BARSIC [14]

Answer:

a) dangers faced during natural circumstances

7 0
2 years ago
On a horizontal frictionless floor, a worker of weight 0.900 kN pushes horizontally with a force of 0.200 kN on a box weighing 1
Ad libitum [116K]

Answer:

D) The worker will accelerate at 2.17  m/s²  and the box will accelerate at 1.08  m/s² , but in opposite directions.

Explanation:

Newton's third law

Newton's third law or principle of action and reaction states that when two interaction bodies appear equal forces and opposite directions. in each of them.

F₁₂= -F₂₁

F₁₂: Force of the box on the worker

F₂₁: Force of the worker on the box

Newton's second law

∑F = m*a

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Formula to calculate the mass (m)

m =  W/g

Where:

W : Weight (N)

g : acceleration due to gravity  (m/s²)

Data

W₁ =1.8 kN   : box weight

W₂ = 0.900 kN : worker weight

F₂₁ = 0.200 kN

F₁₂ = - 0.200 kN

g = 9.8 m/s²

Newton's second law for the box

∑F = m*a

F₂₁ = m₁*a₁    m₁=W₁/g

0.2 kN = (1.8kN)/(9.8 m/s² ) *a₁

a_{1} =\frac{(0.2kN)*9.8\frac{m}{s^{2} } }{1.8 kN}

a₁= 1.08 m/s² : acceleration of the box

Newton's second law for the worker

∑F = m*a

F₁₂ = m₂*a₂ , m₂=W₂/g

- 0.2 kN =( (0.9 kN) /(9.8 m/s² ) )*a₂

a_{1} =\frac{(0.2kN)*9.8\frac{m}{s^{2} } }{0.9 kN}

a₂=  -2.17 m/s² : acceleration of the worker

5 0
3 years ago
A steam power plant with a power output of 200 MW consumes coal at a rate of 700 tons/h. If the heating value of the coal is 40,
RUDIKE [14]

Answer:

η = 2.57%

Explanation:

Given:

Output power of the steam power plant, P(out) = 200 MW

Consumption of coal, m = 700 tons/h = (700 × 10³)/3600 kg/s= 194.44 kg/s

Heating capacity of the coal, Cv = 40000 kJ/kg

now,

Input power,  P(in) = mCv

or

P(in) =  194.44 kg/s × 40000 = 7777.77 MW

thus,

efficiency, η = P(out)/P(in) = (200 MW) / (7777.77 MW) = 0.02571

or

η = 2.57%

3 0
3 years ago
You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 252 N in the negative x di
pentagon [3]

(a) 252 N, opposite to the applied force

There are two forces acting on the refrigerator in the horizontal direction:

- the pushing force of 252 N, F, forward

- the frictional force, Ff, pulling backward

In this case, the refrigerator is not moving: this means that its acceleration is zero. According to Newton's second law, this also means that the net force acting on the refrigerator is also zero:

\sum F = ma = 0

So we have

F-F_f = 0

which means that the frictional force is equal in magnitude to the pushing force:

F_f = F = 252 N

and the direction is opposite to the pushing force.

(b) 334.8 N

The force that must be applied to the refrigerator to make it moving is equal to the maximum force of friction, which is given by:

F_{max} = \mu mg

where

\mu = 0.61 is the coefficient of static friction

m = 56 kg is the mass of the refrigerator

g = 9.8 m/s^2 is the acceleration of gravity

Substituting:

F_max = (0.61)(56 kg)(9.8 m/s^2)=334.8 N

6 0
3 years ago
I understand what makes a kettle so efficient, but what are some improvements you can make to a kettle to increase it’s energy e
shusha [124]

Answer:

Reheat the cold cup of tea or coffee in the microwave. ...

Make iced tea or coffee with what's left. ...

Use a thermos for either tea or coffee.

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3 years ago
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