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Naddika [18.5K]
3 years ago
14

When riding a 10-speed bicycle up a hill, a cyclist shifts the chain to a larger-diameter gear attached to the back wheel. Why i

s this gear preferred to a smaller gear? a. The torque exerted by the chain on the gear is larger. b. The force exerted by the chain on the gear is larger. c. You pedal more frequently to travel the same distance. d. Both a and c are correct.
Physics
1 answer:
dimaraw [331]3 years ago
8 0

To solve this problem we will use the concepts of the moment of rotational inertia, angular acceleration and the expression of angular velocity.

The rotational inertia is expressed as follows:

I = \sum mr^2

Here,

m = Mass of the object

r = Distance from the rotational axis

The rotational acceleration in terms of translational acceleration is

\alpha = \frac{a}{R}

Here,

a = Acceleration

R = Radius of the circular path of the object

The expression for the rotational speed of the object is

\omega = \frac{\Delta \theta}{\Delta t}

Here,

\Delta \theta is the angular displacement of the object

The explanation by which when climbing a mountain uphill is changed to a larger pinion, is because it produces a greater torque but it is necessary to make more pedaling to be able to travel the same distance. Basically every turn results in less rotations of the rear wheel. Said energy that was previously used to move the rotation of the wheel is now distributed in more turns of the pedal. Therefore option a and c are correct.

This would indicate that the correct option is D.

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so, we need

1.29*10*v = 0.3 + 0.54*10*v

or

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180 J of work is done when lifting a box up to a shelf that is 3 m high. What is the mass of the box?
ale4655 [162]

Explanation:

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2 years ago
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8 0
3 years ago
An AC source is connected to a series combination of a light bulb and a variable capacitor. If the capacitance is increased, the
notsponge [240]

Answer:

Increases

Explanation:

Since power P=IV

Then it means when current increases, the power increases hence brightness increases. I represent current, P is power and v is voltage.

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I=2\pi fCV

where I is current across capacitor, f is frequency, C is capacitance and v is voltage across capacitance. From this second formula, it is evident that an increase in capacitance increases the current across the capacitor. Therefore, if current increases, power also increases leading to an increase in brightness

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3 years ago
a radio antenna broadcasts a 1.0 MHz radio wav e with 21 kW of power. Assume that the radiation is emitted uniformly in all dire
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Answer:

I=2.67\times 10^{-6}\ W/m

Explanation:

Given that,

Frequency of a radio antenna is 1 MHz

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I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{21\times 10^3}{4\pi (25000)^2}\\\\I=2.67\times 10^{-6}\ W/m

So, the wave intensity 25 km from the antenna is 2.67\times 10^{-6}\ W/m.

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