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slamgirl [31]
3 years ago
7

A guitar string with a linear density of 2.0 g/m is stretched between supports that are 60 cm apart. The string is observed to f

orm a standing wave with three antinodes when driven at a frequency of 420 Hz.
Part A
What is the frequency of the fifth harmonic of this string?
Physics
1 answer:
Butoxors [25]3 years ago
3 0

<h2>The frequency of driver is 700 Hz</h2>

Explanation:

The frequency of wave in a string is given by the relation

n = \frac{p}{2l} \sqrt{\frac{T}{m} }

here n is the frequency

p is the number of antinodes and l is the length of string .

T is the tension in string and m is the mass per unit length

Thus 420 =\frac{3}{120} \sqrt{\frac{T}{2} }            I

Now if there is 5 antinodes , the value of p = 5

Thus n = \frac{5}{120} \sqrt{\frac{T}{2} }          II

Dividing II by I , we have

n/420 = 5/3

or n = 5/3 x 420 = 700 Hz

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5 seconds is a poor time to ask about, because the speed abruptly changes at exactly 5 seconds.

Up until that time, the speed has been 1 m/s. And then, at exactly 5 seconds, it becomes zero.
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4 0
3 years ago
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a guitar string is 0.620 m long, and oscillates at 234 Hz. if a player uses his finger to shorten the string to 0.480 m, what is
Nutka1998 [239]
Solve the x u will get 181.16

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3 years ago
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The magnetic force on a straight wire 0.69 m long is 1.5 x 10-3 N. The current in the wire is 16.9 A. What is the magnitude of t
VikaD [51]

Answer:

Magnitude of magnetic field is 1.29 x 10⁻⁴ T

Explanation:

Given :

Current flowing through the wire, I = 16.9 A

Length of wire. L = 0.69 m

Magnetic force experienced by the wire, F = 1.5 x 10⁻³ N

Consider B be the applied magnetic field.

The relation to determine the magnetic force experienced by current carrying wire is:

F = ILBsinθ

Here θ is the angle between magnetic field and current carrying wire.

According to the problem, the magnetic field and current carrying wire are perpendicular to each other, that means θ = 90⁰. So, the above equation becomes:

F = ILB

B=\frac{F}{IL}

Substitute the suitable values in the above equation.

B=\frac{1.5\times10^{-3} }{16.9\times0.69}

B = 1.29 x 10⁻⁴ T

7 0
3 years ago
A siren on the top of the police car emits sound at frequency of 823 Hz. The car is approaching a bystander on a sidewalk at spe
statuscvo [17]

Answer:

The bystander will hear a frequency of 931.18 Hz.

Explanation:

let V = 39.5 m/s be velocity of the police car and Fs be the frequency a siren of the police car emits. let v = 0 m/s be the velocity of the bystander and Vs = 340 m/s is the velocity of sound in air.

then, we know that the bystander has to hear a higher frequency than the one emitted and the frequency that the bystander hears is given by the doppler relation:

Fo = [(Vs)/(Vs - V)]×Fs

      = [(Vs)/(Vs - V)]×Fs

      = [(340)/(340 - 39.5)]×(823)

      = 931.18 Hz

Therefore, the bystander will hear a frequency of 931.18 Hz.

3 0
3 years ago
If a certain brand of solar panels is rated at a value of 1.50 KW/m2 , and a person needed to generate 2.50 MJ in an hour, what
alisha [4.7K]

Answer:

A=0.462\ m^2

Explanation:

Power rating of a solar panel is 1.50 KW/m²

It generates 2.50 MJ in an hour.

We need to find the area of this type of solar panel would be needed. The power pertaining to generate this energy is given by :

P=\dfrac{2.5\times 10^6}{1\ h}\\\\P=\dfrac{2.5\times 10^6}{3600\ s}\\\\P=694.44\ W

Let A be the area of the solar panel. It is calculated as follows :

\dfrac{P}{A}=1.5\times 10^3\\\\A=\dfrac{694.44}{1.5\times 10^3}\\A=0.462\ m^2

So, the required area of the solar panel is 0.462\ m^2.

4 0
2 years ago
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