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umka21 [38]
3 years ago
12

If a gene encoding a protein whose third amino acid is tyrosine is affected by a single nucleotide substitution in that tyrosine

codon, how many of the other 19 amino acids could possibly end up replacing tyrosine as the third amino acid?
Chemistry
1 answer:
Sergio [31]3 years ago
4 0

Answer:

6 different amino acids (no including Stop codons)

Explanation:

First of all, it is necessary to know that tyrosine is an amino acid coded by two different codons: UAU and UAC.

If there's a single nucleotide substitution, we need to redefine the new possible codons:

For UAU:

- Substitution in the first nucleotide:

* CAU: His

* GAU: Asp

* AAU: Asn

- Substitution in the second nucleotide:

* UCU: Ser

* UGU: Cys

* UUU: Phe

- Substitution in the third nucleotide:

* UAG: Stop

* UAC: Tyr

* UAA: Stop

For UAC:

- Substitution in the first nucleotide:

* CAC: His

* GAC: Asp

* AAC: Asn

- Substitution in the second nucleotide:

* UUC: Phe

* UGC: Cys

* UCC: Ser

- Substitution in the third nucleotide:

* UAG: Stop

* UAA: Stop

* UAC: Tyr

Possible amino acids replacing tyrosine (His, Asp, Asn, Phe, Cys, Ser)

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10. A small helium tank claims to be able to fill 30 balloons to a volume of 3.15 L
Sindrei [870]

Taking into account the Boyle's law, 3.377 L of helium the tank will be able to  produce at a pressure of 94.2 kPa.

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature, and moles.

Boyle's law is one of the gas laws that relates the volume and pressure of a certain quantity of gas kept at constant temperature.

This law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. That is, if the pressure increases, the volume decreases; while if the pressure decreases, the volume increases.

Mathematically, Boyle's law states that the product of pressure and volume is constant:

P×V= k

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

P1× V1= P2×V2

In this case, you know:

  • P1= 101 kPa
  • V1= 3.15 L
  • P2= 94.2 kPa
  • V2= ?

Replacing in Boyle's law:

101 kPa× 3.15 L= 94.2 kPa× V2

Solving:

V2=\frac{101 kPa x3.15 L}{94.2 kPa}

<u><em>V2= 3.377 L</em></u>

In summary, 3.377 L of helium the tank will be able to  produce at a pressure of 94.2 kPa.

Learn more:

brainly.com/question/4147359?referrer=searchResults

7 0
3 years ago
In thermodynamics, we determine the spontaneity of a reaction by the sign of ΔG. In electrochemistry, spontaneity is determined
faltersainse [42]

<u>Answer:</u>

<u>For A:</u> The standard cell potential of the reaction is 4.4 V

<u>For B:</u> The standard Gibbs free energy of the reaction is -8.50\times 10^5J

<u>For C:</u> The reaction is spontaneous as written.

<u>Explanation:</u>

  • <u>For A:</u>

The given chemical reaction follows:

2Li(s)+Cl_2(g)\rightarrow 2Li^+(aq.)+2Cl^-(aq.)

The given half reaction follows:

<u>Oxidation half reaction:</u>  Li(s)\rightarrow Li^+(aq.)+e^-;E^o_{Li^+/Li}=-3.04V ( × 2)

<u>Reduction half reaction:</u>  Cl_2(g)+2e^-\rightarrow 2Cl^-(aq.);E^o_{Cl_2/2Cl^-}=+1.36V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction.

Here, chlorine will undergo reduction reaction will get reduced.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=1.36-(-3.04)=4.4V

Hence, the standard cell potential of the reaction is 4.4 V

  • <u>For B:</u>

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}

where,

n = number of electrons transferred = 2mol\text{ e}^-

F = Faradays constant = 96500J/V.mol\text{ e}^-

E^o_{cell} = standard cell potential = 4.4 V

Putting values in above equation, we get:

\Delta G^o=-2\times 96500\times 4.4=-849200J=-8.50\times 10^5J

Hence, the standard Gibbs free energy of the reaction is -8.50\times 10^5J

  • <u>For C:</u>

For a reaction to be spontaneous, the standard Gibbs free energy change of the reaction must be negative.

From above, the standard Gibbs free energy change of the reaction is coming out to be negative.

Hence, the reaction is spontaneous as written.

7 0
4 years ago
What ions are associated with bases
Setler [38]
Hydroxide ions are what you are looking for. When hydroxide ions are released, the solution becomes more basic
4 0
3 years ago
Can anyone help with any of these questions :)
hoa [83]

Answer: 1.D

2. A

3. D

Explanation:

6 0
3 years ago
What is the volume of 1.9 moles of chlorine gas (Cl2) at 298 K and 1.3 atm?
matrenka [14]
<h2>Hello!</h2>

The answer is:

The correct option is option C.

V=36L

<h2>Why?</h2>

To calculate the volume of the gas sample, we need to use the Ideal Gas Law, this equation is used to relate the pressure, the volume, the mass and the temperature of a gas, so, we can isolate the volume from it.

The Ideal Gas Law equation is equal to:

PV=nRT

Where,

P is the pressure (in atm)

V is the volume (in liter)

n is the mass of the gass (in mole)

T is the temperature of the gass (absolute temperature)

So, from the statement we know that:

Pressure=1.3atm\\Temperature=298K\\n=1.9moles\\R=0.082057\frac{L.atm}{mol.K}

Then, substituting and calculating we have:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1.9moles*0.082057\frac{L.atm}{mol.K}*298K}{1.3atm}=35.74L

Now, rounding to the nearest whol number we have that the volume is equal to 36 L.

Hence, the correct option is option C.

Have a nice day!

5 0
3 years ago
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