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bonufazy [111]
3 years ago
7

The distance between Pluto and the Sun is 39.1 times more than the distance between the Sun and Earth. Calculate the time taken

by Pluto to orbit the Sun in Earth days.
Physics
1 answer:
german3 years ago
7 0

Answer:

Explanation:

Given

Distance between Pluto and sun is 39.1 times more than the distance between earth and sun

According to Kepler's Law

T^2=kR^3

where k=constant

T=time period

R=Radius of orbit

Suppose R_1 is the radius of orbit of earth and sun

so Distance between Pluto and sun is R_2=39.1\cdot R_1

T_1 and T_2 is the time period corresponding to R_1 and R_2[/tex]

(T_1)^2=k(R_1)^3---1

(T_2)^2=k(R_2)^3---2

divide 1 and 2

(\frac{365}{T_2})^2=(\frac{R_1}{39.1})^3

T_2^2=365^2\times 39.1^3

T_2=89239.67\ Earth\ days                      

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A child of mass M is swinging on a swing set. The ropes attaching the swing to the top bar have length L. Find the gravitational
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Answer:

(a) 0

(b) 10ML

(c) 10ML(1 - cos(\theta))

(d) 10ML(1 + sin(\phi))

Explanation:

(a) When hanging straight down. The child is at the lowest position. His potential energy with respect to this point would also be 0.

(b) Since the rope has length L m. When the rope is horizontal, he is at L (m) high with respect to the lowest swinging position. His potential energy with respect to this point should be

E_h = mgh = 10ML

where g = 10m/s2 is the gravitational acceleration.

(c) At angle \theta from the vertical. Vertically speaking, the child should be at a distance of Lcos(\theta) to the swinging point, and a vertical distance of L - Lcos(\theta) to the lowest position. His potential energy to this point would be:

E_{\theta} = mgh = 10M(L - Lcos(\theta)) = 10ML(1 - cos(\theta))

(d) at angle \phi from the horizontal. Suppose he is higher than the horizontal line. This would mean he's at a vertical distance of Lsin(\phi) from the swinging point and higher than it. Therefore his vertical distance to the lowest point is L + Lsin(\phi) = L(1 + sin(\phi))

His potential energy to his point would be:

E_{\phi} = mgh = 10ML(1 + sin(\phi))

5 0
4 years ago
How many quantum numbers are used to describe the energy state of an electron in an atom
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The 1 kg box is sliding along a frictionless surface. It collides with and sticks to the 2 kg box. Afterward, the speed of the t
UNO [17]

Answer:

The correct option is (E).

Explanation:

Given that,

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Mass of object 2, m₂ = 2 kg

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The initial speeds of both boxes is not given. So, we can't put the values of their speeds in the momentum conservation equation.

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7) A force of 500N exists between two identical point charges separated by a dis-
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Explanation:

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5 0
3 years ago
Read 2 more answers
2.Given the velocity versus time graph shown below, sketch the corresponding position versustimeand acceleration versus timegrap
Papessa [141]

Graphical analysis of motion gives the graphical the relationships between position, velocity, and acceleration, versus time

2. Please find attached the required position versus time and acceleration versus time graphs

3. Please find attached the required velocity versus time and position versus time graphs

The reasons the attached graphs are correct are given as follows:

2. The given coordinates of the vertex points obtainable from the graph is first written as follows:

\begin{array}{|c|c|c|c|c|}\underline  {Time, \ t}&\underline  {Velocity, \ v}&Acceleration, a&\underline  {Distance , \ s =v\cdot \Delta t+\dfrac{1}{2} \cdot a \cdot (\Delta t)^2}&Position\\0&-1&0&0&0\\2&1&1&0&0\\4&-1&-1&0&0\\6&1&1&0&0\\10&1&0&4&4\\12&0&-0.5&1&5\end{array}The distance covered between time intervals of time, <em>s</em>, is given as follows;

s = v \cdot \Delta t + (1/2) \cdot a  \cdot ( \Delta t)^2

The position, Pₙ = s₁ + s₂ + s₃ + ... + sₙ

Other values on the graph obtained by calculation on a spreadsheet are;

\begin{array}{|l|cl|}Time \ (s)&&Position \ (m)\\0.5&&-0.375\\1&&-0.5\\1.5&&-0.375\\2.5&&0.375\\3&&0.5\\3.5&&0.375\\4.5&&-0.375\\5&&-0.5\\5.5&&-0.375\\6.5&&0.5\\7&&1\\7.5&&1.5\\8&&2\\8.5&&2.5\\9&&3\\10&&4\\10.5&&4.4375\\11&&4.75\\11.5&&4.9375\\12&&5\end{array}\right]

Please find attached the acceleration versus time graph

3. The coordinates of the points are presented as follows:

\begin{array}{|c|cc|}\underline{Time\ (s)}&&\underline{Acceleration\ (m/s^2)}\\0&&0.5\\2&&0.5\\2&&0\\4&&0\\4&&-0.5\\6&&-0.5\\6&&0\\8&&0\\8&&0.5\\10&&0.5\\10&&-0.5\\12&&-0.5\end{array}\right]

The distance covered between time intervals, <em>s</em>, is given as follows;

s = v \cdot \Delta t + (1/2) \cdot a  \cdot ( \Delta t)^2

The position, Pₙ = s₁ + s₂ + s₃ + ... + sₙ

Using a spreadsheet application, more detailed values of the position can be found as shown in the graph created with MS Excel

  • Time

0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6, 6.5, 7, 7.5, 8, 8.5, 9, 9.5, 10, 10.5, 11, 11.5, 12

  • Position

0, 0.06, 0.25, 0.56, 1.00, 1.50, 2, 2.5, 3, 3.5, 3.81, 4.00, 4.06, 4.06, 4.06, 4.06, 4.06, 4.13, 4.31, 4.63, 5.06, 5.50, 5.81, 6, 6.06

Learn more about graphing motion here:

brainly.com/question/11826205

7 0
3 years ago
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