Complete Question
A parallel-plate capacitor has square plates 20 cm on a side and 0.50 cm apart. If the voltage across the plates is increasing at the rate of 220 V/s, what is the displacement current in the capacitor?
Answer:
The value is
Explanation:
From the question we are told that
The length and breath of the square plate is
The distance of separation between each plate is
The rate of voltage increase is
Generally the charge on the plate is mathematically represented as
Now C is the capacitance of the capacitor which is mathematically represented as
Here A is the cross-sectional area which is mathematically represented as
=>
=>
So
Now the change of the charge flowing through the plates with time is mathematically represented as
So
Generally
So