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lara [203]
3 years ago
14

Suppose that an object travels from one point in space to another. Make a comparison between the magnitude of the displacement a

nd the distance traveled by this object.
Physics
1 answer:
Rashid [163]3 years ago
3 0

Answer:

- Distance is a scalar quantity, defined as the total amount of space covered by an object while moving between the final position and the initial position. Therefore, it depends on the path the object has taken: the distance will be minimum if the object has travelled in a straight line, while it will be larger if the object has taken a non-straight path.

- Displacement is a vector quantity, whose magnitude is equal to the distance (measured in a straight line) between the final position and the initial position of the object. Therefore, the displacement does NOT depend on the path taken, but only on the initial and final point of the motion.

If the object has travelled in a straight path, then the displacement is equal to the distance. In all other cases, the distance is always larger than the displacement.

A particular case is when an object travel in a circular motion. Assuming the object completes one full circle, we have:

- The distance is the circumference of the circle

- The displacement is zero, because the final point corresponds to the initial point

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A battery can be modeled as a source of emf in series, with both a resistance of 10Ωand an inductive reactance of 5
Fiesta28 [93]

Answer:

Explanation:

For circuit in resonance , inductive and capacitive reactance should be equal. Since in the given circuit ,  these two are not equal, the circuit is not in resonance. It does not depend upon voltage provided.

option b is correct.

With this load, the  fraction of the average power, put out by the source of emf,  delivered to the load can be calculated as follows

Power delivered to resistor will be 2/3 rd of total power delivered by source because resistance has value twice that of reactance of capacitor.  So the correct option is .7

option D ) is correct.

3 0
4 years ago
2. Grace drives her car 40 km in 75 minutes. What is her average speed in<br> kilometers per hour?
Agata [3.3K]

Answer:

k

Explanation:

k

3 0
3 years ago
Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 4.50 m above
Virty [35]

8.98×10^6\:\text{m}

Explanation:

First we need to find the acceleration due to gravity on the planet. The wrench took 0.809 s to fall from a height of 4.50 m so we can use the equation

y = -\frac{1}{2}gt^2

Solving for g, we get

g = -\dfrac{2y}{t^2} = -\dfrac{2(-4.50\:\text{m})}{(0.809\:\text{s})} = 13.8\:\text{m/s}^2

Recall that the acceleration due to gravity on a planet's surface can be written as

g = G\dfrac{M_p}{R_p^2}

We can express the mass of the planet M_p in terms of its density \rho as follows:

M_p = \rho \left(\dfrac{4\pi}{3}R_p^3\right) = \dfrac{4\pi}{3}\rho R_p^3

The expression for g then becomes

g = \dfrac{G}{R_p^2} \left(\dfrac{4\pi}{3}\rho R_p^3\right) = \dfrac{4\pi G}{3}\rho R_p

Solving for R_p, we get

R_p = \dfrac{3g}{4\pi G\rho}

\:\:\:\:\:\:\:= \left[\dfrac{3(13.8\:\text{m/s}^2)}{4\pi (6.674×10^{-11}\:\text{Nm}^2\text{/kg}^2)(5500\:\text{kg/m}^3)}\right]

\:\:\:\:\:\:\:= 8.98×10^6\:\text{m}

3 0
3 years ago
The height of a wave crest is called __________________________. a energy b rest position c amplitude d freqency e wavelength
Sladkaya [172]
B. rest position
  hope this helps!!!
7 0
3 years ago
A radio wave has a frequency of 5.5 × 104 hertz and travels at a speed of 3.0 × 108 meters/second. What is its wavelength?
tigry1 [53]

Answer:5.45X10^3m

Explanation:So use the formula,v= fλ

3X10^8=5.5X10^4λ what Im saying is divide both and u should get 5454.54m but do sig figs to get answer

3 0
3 years ago
Read 3 more answers
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