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kiruha [24]
3 years ago
7

Which quantum numbers must be the same for the orbitals that they designate to be degenerate in a many-electron system?

Physics
1 answer:
stealth61 [152]3 years ago
8 0
<span>For the orbitals that designate to be degenerate in a many-electron system, the following quantum numbers should be equal:
1- principle quantum number (n) : this describes the most probable distance of the electron from the nucleus
2- o</span><span>rbital angular momentum quantum number (l) : this determines the shape of the orbital </span>
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<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>QUESTION)</u></h3>

<em>✔ We have: KE = PE (potential energy) </em>

<em>PE = m x g x h </em>

The potential energy that the pebble of mass 1 has is called PE1 and the potential energy that the pebble of mass 2 has is called PE2  

PE1 = PE2 ⇔ PE1/PE2 = 1

\frac{m_1\times g\times h}{m_2\times g\times 4h} = 1 \\ \\  \frac{m_1}{m_2\times 4} = 1 \\ \\  \frac{m_1}{m_2} = 4

The mass m1 is therefore 4 times greater than that of the stone of mass m2.

 

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Discuss the effects of breaking a food chain.
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Explanation:

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3 years ago
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3 0
3 years ago
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a piece of metal with a mass of 15.3 grams has a temperature of 50.0°C. When the metal is placed in 80.2 grams of water at 21.0°
AleksAgata [21]

Answer:

1.21

Explanation:

Heat rise in the body happens due to heat supplied by water to the body.

Heat rise in body = m₁ c₁ ΔT₁

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Heat lost from water to the body = m₂ c₂ ΔT₂

Where m₂ is mass of water and c₂ is its specific heat of water ( c₂ =1 (since water))

Equating both:

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⇒   c₁ = 80.2 / (15.3 x 4.3) = 1.21

6 0
3 years ago
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