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ICE Princess25 [194]
3 years ago
6

Why do experiment need to be repeatable ?​

Chemistry
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

So you know that the same thing can happen no matter the circumstances.

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Why is it useful to use moles to measure chemical quantities?
PtichkaEL [24]
It takes into account the different molecular masses of the different chemicals by providing a fixed and standardised number of molecules/ atoms for chemicals to be measured
6 0
3 years ago
what is the density of an object that has a mass of 550 grams and displaces 25 ml of water? select all that apply. 22 ml/g .04 m
Black_prince [1.1K]
Density = mass / volume

D = 550 / 25

D = 22 g/mL

hope this helps!
3 0
3 years ago
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What is the percent by weight of sodium in sodium sulfate (Na2SO4)? (The molar mass of Na = 22.99, S = 32.07, and O = 16.00.) 16
34kurt
The total mass would be 142.05 g/mol. Since sodium is 22.99 g/mol and there are 2 sodium atoms, it would be 45.98 g/mol. Divide 45.98 by 142.05 and you get 32.37%
8 0
4 years ago
Read 2 more answers
Find the element. Plz help!
Hunter-Best [27]

Answer:

Hydrogen.

Explanation:

We see in the nucleus that we have 1 proton and 1 neutron.

The number of protons in the nucleus determines which element it is.

Element with 1 proton is the 1st element on the Periodic Table, Hydrogen.

4 0
3 years ago
The first two steps in the industrial synthesis of nitric acid produce nitrogen dioxide from ammonia: 2N0(g) +02(g) 2NO2 (g) The
Tresset [83]

The question is incomplete, complete question is :

The first two steps in the industrial synthesis of nitric acid produce nitrogen dioxide from ammonia:

Step 1 : 4NH_3(g)+5O_2(g)\rightleftharpoons 4NO(g)+6H_2O(g)

Step 2 :  2NO(g) +O_2(g) \rightleftharpoons 2NO_2 (g)

The net reaction is:

4NH_3(g)+7O_2(g)\rightleftharpoons 4NO_2(g)+6H_2O(g)

Write an equation that gives the overall equilibrium constant K in terms of the equilibrium constants K_1 and K_2. If you need to include any physical constants, be sure you use their standard symbols

Answer:

Equation that gives the overall equilibrium constant K in terms of the equilibrium constants K_1 \& K_2:

K=K_1\time (K_2)^2

Explanation:

Step 1 : 4NH_3(g)+5O_2(g)\rightleftharpoons 4NO(g)+6H_2O(g)

Expression of an equilibrium constant can be written as:

K_1=\frac{[NO]^4[H_2O]^6}{[NH_3]^4[O_2]^5}

Step 2 :  2NO(g) +O_2(g) \rightleftharpoons 2NO_2 (g)

Expression of an equilibrium constant can be written as:

K_2=\frac{[NO_2]^2}{[NO]^2[O_2]}

The net reaction is:

4NH_3(g)+7O_2(g)\rightleftharpoons 4NO_2(g)+6H_2O(g)

Expression of an equilibrium constant can be written as:

K=\frac{[NO_2]^4[H_2O]^6}{[NH_3]^4[O_2]^7}

Multiply and divide [NO]^4;

K=\frac{[NO_2]^4[H_2O]^6}{[NH_3]^4[O_2]^7}\times \frac{[NO]^4}{[NO]^4}

K=\frac{[NO]^4[H_2O]^6}{[NH_3]^4[O_2]^7}\times \frac{[NO_2]^4}{[NO]^4}

K=K_1\times \frac{[NO_2]^4}{[O_2]^2[NO]^4}

K=K_1\times (\frac{[NO_2]^2}{[O_2]^1[NO]^2})^2

K=K_1\time (K_2)^2

So , the equation that gives the overall equilibrium constant K in terms of the equilibrium constants K_1 \& K_2:

K=K_1\time (K_2)^2

4 0
3 years ago
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