Question

A train departs from its station at a constant acceleration of 5 m/s. What is the speed of the train at the end of 20s?

Answer 1

Answer:

Velocity, v = 100 m/s

Explanation:

It is given that,

Initial speed of the train, u = 0

Acceleration of the train, $a=5\ m/s^2$

Let v is the velocity of the train at the end of 20 seconds, t = 20 s

Using the equation of kinematics as :

v = u + a × t

v = a × t

v = 5 × 20

v = 100 m/s

So, the velocity of the train after 20 s is 100 meters. Hence, this is the required solution.

Answer 2

Acceleration = (final velocity-initial velocity)/time
5 = (v-0)/20
v = 100m/s