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Virty [35]
3 years ago
5

15) A 1720 kg car accelerates at a rate of 3.0 m/s2. How much force is the car's engine producing? (use the formula F=ma

Physics
2 answers:
AleksAgata [21]3 years ago
5 0

Answer:

5160 N

Explanation:

Anastasy [175]3 years ago
4 0

Answer:

<h3>The answer is 5160 N</h3>

Explanation:

To find the force acting on an object given it's mass and acceleration we use the formula

<h3>Force = mass × acceleration</h3>

From the question

mass = 1720 kg

acceleration = 3.0 m/s²

We have

Force = 1720 × 3

We have the final answer as

<h3>5160 N</h3>

Hope this helps you

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Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work?
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Based on the law of conservation of energy, we know that we can't create energy, machines can only convert one type of energy into another. So, if we want to improve a machines's ability then we need to reduce it's loss energy (part of energy which is useless). Out of all the options only Option C fits best with it.

In short, Your Answer would be Option C

Hope this helps!
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3 years ago
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Identify the ways in which carbon is added to the atmosphere?
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5 0
3 years ago
An inductor is connected to the terminals of a battery that has an emf of 16.0 V and negligible internal resistance. The current
balu736 [363]

Answer:

(a) The resistance R of the inductor is 2480.62 Ω

(b) The inductance L of the inductor is 1.67 H

Explanation:

Given;

emf of the battery, V = 16.0 V

current at 0.940 ms = 4.86 mA

after a long time, the current becomes 6.45 mA = maximum current

Part (a) The resistance R of the inductor

R = \frac{V}{I_{max}} = \frac{16}{6.45*10^{-3}} = 2480.62 \ ohms

Part (b)  the inductance L of the inductor

\frac{Rt}{L} = -ln(1-\frac{I}I_{max}})\\\\L = \frac{Rt}{-ln(1-\frac{I}I_{max})}}

where;

L is the inductance

R is the resistance of the inductor

t is time

L = \frac{Rt}{-ln(1-\frac{I}I_{max})}} = \frac{2480.62*0.94*10^{-3}}{-ln(1-\frac{4.86}{6.45})} \\\\L =\frac{2.3318}{1.4004} = 1.67 \ H

Therefore, the inductance is 1.67 H

5 0
3 years ago
A golfer hits a 42 g ball, which comes down on a tree root and bounces straight up with an initial speed of 15.6 m/s. Determine
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Answer:

12.2 m

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Given:

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v = 0 m/s

a = -10 m/s²

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(0 m/s)² = (15.6 m/s)² + 2 (-10 m/s²) Δy

Δy = 12.2 m

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A cruise started its trip 8:00. Its average speed was 100 km/h.
Aneli [31]

Answer:

120 k/m

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