All categories

3 years ago

The number of individuals an environment can sustain for an indefinite period of time is called its

1 answer:

swat323 years ago

7 0

<span>C. Carry capacity
</span>Carry capacity is defined as the maximum population size of a species that an environment can sustain indefinitely. It is also defined as the environment's maximal load of a species. Factors that impact on the carrying capacity of a species are the availability of food and water, raw materials to build shelter, the environment's ability to process waste products, as well as the species' ability to reproduce.

You might be interested in

What percentage of the filtrate's water that enters bowman's capsule is reabsorbed into the blood? select one:

maksim [4K]

99% of the filtrate's water that enter bowman's capsule is reabsorbed into the blood. This is because the water and the salts contained in the filtrate are needed for optimal functioning of the body system.

3 0

3 years ago

Calculate the electric double layer thickness of a alumina colloid in a dilute (0.1 mol/dm3) CsCI electrolyte solution at 30 °C.

Ad libitum [116K]

Explanation:

The given data is as follows.

Concentration = 0.1 $mol/dm^{3}$

= 0.1 \frac{mol dm^{3}}{dm^{3}} \frac{10^{3}}{dm^{3}} \times \frac{6.022 \times 10^{23}}{1 mol} ions

= $6.022 \times 10^{25} ions/m^{3}$

T = $30^{o}C$ = (30 + 273) K = 303 K

Formula for electric double layer thickness ( $\lambda_{D}$ ) is as follows.

$\lambda_{D}$ = $\frac{1}{k} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}$

where, $n^{o}$ = concentration = $6.022 \times 10^{25} ions/m^{3}$

Hence, putting the given values into the above equation as follows.

$\lambda_{D}$ = $\sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}$

= $\sqrt \frac{78 \times 8.854 \times 10^{-12} c^{2}/Jm \times 1.38 \times 10^{-23}J/K \times 303 K}{2 \times 6.022 \times 10^{25} ions/m^{3} \times (1)^{2} \times (1.6 \times 10^{-19}C)^{2}}$

= $9.669 \times 10^{-10}$ m

or, = $9.7 A^{o}$

= 1 nm (approx)

Also, it is known that $\lambda_{D}$ = $\sqrt \frac{1}{n^{o}}$

Hence, we can conclude that addition of 0.1 $mol/dm^{3}$ of KCl in 0.1 $mol/dm^{3}$ of NaBr " $\lambda_{D}$ " will decrease but not significantly.

7 0

3 years ago

Lithium is a metal.

Zina [86]

Answer:

Explanation:

lithium: lithium is very soft, silvery metal. melting point is 180.54°C and boiling point is 1,335°C. it's density is 0.534 grams per cu.cm. oxygen: oxygen is colourless , odorless , tasteless gas

8 0

3 years ago

What is the effect of dilution on the pH of a buffer?

OLEGan [10]

I wish I knew I’m sorry

3 0

3 years ago

Read 2 more answers

Rain washing away soil from a hillside

Aneli [31]

Answer:

deposition