Answer:14.14 cm
Explanation:
Given
Spring Compression ![x=12 cm](https://tex.z-dn.net/?f=x%3D12%20cm)
Potential energy Stored in spring![=72 J](https://tex.z-dn.net/?f=%3D72%20J)
Suppose k is the spring constant of spring
Potential Energy of spring is given by ![=\frac{kx^2}{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bkx%5E2%7D%7B2%7D)
![\frac{k(0.12)^2}{2}=72](https://tex.z-dn.net/?f=%5Cfrac%7Bk%280.12%29%5E2%7D%7B2%7D%3D72)
![k(0.12)^2=144](https://tex.z-dn.net/?f=k%280.12%29%5E2%3D144)
![k=10,000 N/m](https://tex.z-dn.net/?f=k%3D10%2C000%20N%2Fm)
![k=10 kN/m](https://tex.z-dn.net/?f=k%3D10%20kN%2Fm)
for 100 J energy
![\frac{k(x_0)^2}{2}=100](https://tex.z-dn.net/?f=%5Cfrac%7Bk%28x_0%29%5E2%7D%7B2%7D%3D100)
![10\times 10^3\cdot (x_0)^2=200](https://tex.z-dn.net/?f=10%5Ctimes%2010%5E3%5Ccdot%20%28x_0%29%5E2%3D200)
![(x_0)^2=2\times 10^{-2}](https://tex.z-dn.net/?f=%28x_0%29%5E2%3D2%5Ctimes%2010%5E%7B-2%7D)
![x_0=0.1414](https://tex.z-dn.net/?f=x_0%3D0.1414)
![x_0=14.14 cm](https://tex.z-dn.net/?f=x_0%3D14.14%20cm)
The energy of a wave is directly proportional to the square of the amplitude of the wave.
<h3>What is the relationship between energy and amplitude?</h3>
There is direct relationship between energy of the wave and the amplitude of the wave. The energy transported by a wave is directly proportional to the square of the amplitude of the wave. This means if energy is increase the amplitude of wave becomes double and vice versa.
Energy = (amplitude)2
So we can conclude that the energy of a wave is directly proportional to the square of the amplitude of the wave.
Learn more about energy here: brainly.com/question/13881533
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Nichrome wire. That's the stuff that toasters are made from. The resistance is pretty high, considering the diameter. 1 meter is at about the same guage as that listed below for copper is about 96 ohms.
Most of the time you are trying to use wire with the least resistance.
A meter of copper has a listed resistance of 0.024 ohms / meter. The wire is a 19 guage wire which makes it pretty thin.
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I'm not sure what you are asking. If want the resistance of something in terms of what would increase the resistance of the same material for both calculations then
Rule 1: It you decrease the wire diameter, you increase the resistance
Rule 2: If you increase the length of the wire, you increase the resistance.
Both rules assume you are using something like copper.
Let's ask this question step by step:
Part A)
a x b = (3.0i + 5.0j) x (2.0i + 4.0j) = (12-10) k = 2k
ab = (3.0i + 5.0j). (2.0i + 4.0j) = 6 + 20 = 26
Part (c)
(a + b) b = [(3.0i + 5.0j) + (2.0i + 4.0j)]. (2.0i + 4.0j)
(a + b) b = (5.0i + 9.0j). (2.0i + 4.0j)
(a + b) b = 10 + 36
(a + b) b = 46
Part (d)
comp (ba) = (a.b) / lbl
a.b = (3.0i + 5.0j). (2.0i + 4.0j) = 6 + 20 = 26
lbl = root ((2.0) ^ 2 + (4.0) ^ 2) = root (20)
comp (ba) = 26 / root (20)
answer
2k
26
46
26 / root (20)