Answer:
the spring constant is -89.2857 n/m
Explanation:
The computation of the spring constant is shown below:
As we know that
Force in newtons = Spring constant × amount of extension
F = -k × x
where
F = 25 N
And, x = 0.280m
So, the spring constant would 2
= 25N ÷ 0.280 m
= -89.2857 n/m
Hence the spring constant is -89.2857 n/m
The mass of the man would remain the same…
His weight would change. Assuming the man’s weight on earth is 60N.
Since weight is a force, according to Newton’s second law, F = ma ( m = mass, a = acceleration due to gravity) First lets find the mass of the man, as it is required to find his weight on the moon.
F=ma[taking a of earth as10m/s
2
]
60=m.10[divide10onbothsides]
m=
10
60
= 6 Kg
Acceleration due to gravity on the moon is83%less than the acceleration due to gravity on earth(1.622m/s
2
).
F=ma
F=6.1.622=9.732 N
So a person weighting 60N on earth would approximately weight around 10Non the moon.
Complete Question
1. What is the linear speed of a point on the edge of a 0.30 m diameter grinding wheel rotating at 1600 rpm?
2. What is the acceleration of the point?
Answer:
1
2
Explanation:
From the question we are told that
The diameter is 
The angular speed is 
Generally the is mathematically represented as
Generally the linear speed is mathematically represented as
Generally the acceleration is mathematically represented as
Answer:
1/R = 1/R1 + 1/R2 + 1/R3
1/1 + 1/2 + 1/4 = 1 + .5 + .25 = 1.75
1/1.75 = .572
multiplying this by 100 gives us
R = 57.2 ohms
The smallest resistor (100 ohms) will draw the most current
(One can also use R = R1 R2 R3 / (R1 R2 + R1 R3 + R2 R3)
Answer:
Sagittarius A
At its center, surrounded by 200-400 billion stars and undetectable to the human eye and by direct measurements, lies a supermassive black hole called Sagittarius A*, or Sgr A* for short. The Milky Way has the shape of a spiral and rotates around its center, with long curling arms surrounding a slightly bulging disk.
Explanation:
