Answer:
[Na₂CO₃] = 0.094M
Explanation:
Based on the reaction:
HCO₃⁻(aq) + H₂O(l) ↔ CO₃²⁻(aq) + H₃O⁺(aq)
It is possible to find pH using Henderson-Hasselbalch formula:
pH = pka + log₁₀ [A⁻] / [HA]
Where [A⁻] is concentration of conjugate base, [CO₃²⁻] = [Na₂CO₃] and [HA] is concentration of weak acid, [NaHCO₃] = 0.20M.
pH is desire pH and pKa (<em>10.00</em>) is -log pka = -log 4.7x10⁻¹¹ = <em>10.33</em>
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Replacing these values:
10.00 = 10.33 + log₁₀ [Na₂CO₃] / [0.20]
<em> [Na₂CO₃] = 0.094M</em>
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Option B is correct
K = Kp /Kr
The given equation indicating, the product containing 6 moles of proton whereas the reactant contains 2 mole of bismuth and 3 mole of hydrogen sulphide.
Hence, in reaction B there are 2 mole of bismuth and 3 mole of hydrogen sulphide reacting to produce 6 moles of proton. whereas the concentration of Bi2S3 is not considered as it is present in solid phase.
Answer:
did not understand a thing
PHYSICAL and CHEMICAL PROPERTIES of sodium hydroxide!
Chemical formula: NaOH
Molecular weight: 40.01
Synonyms: White caustic, caustic soda, soda lye, lye
CAS number: 1310–73–2
Melting point: 318. 4°C
Boiling point: 1390°C
Specific gravity: 2.13
Solubility: Soluble in water, ethanol and glycerol; insoluble in acetone and ether
Answer:
There will be 3 peaks.
Relative height of the atomic peaks would be; 158, 160 and 162
Explanation:
We are told that Bromine has two isotopes namely 79Br and 81Br in a 1 : 1 ratio (50 : 50).
This means that a compound which contains 1 bromine atom will have two peaks in the molecular ion region but it depends on which bromine isotope is contained in the molecular ion.
Thus;
Relative height of atomic peaks is given by;
m/z = 79Br¯ 79Br+ = 158
79Br¯ 81Br+ = 160
81Br¯ 81Br+ = 162