How has light been described? As a force and a wave only as a particle only as a force as a particle and a wave only as a wave

A small earthquake starts a lamppost vibrating back and forth. The amplitude of the vibration of the top of the lamppost is 7.0

krok68 [10]

Answer:

(a) T=6.07s

(b) $x_{max|4.0s}=3.62cm$

Explanation:

For Part (a)

The initial amplitude is given as A=7.0 cm

Apply the equation $x_{max}(t)=Ae^{-t/T}$ with $x_{max}(7.6s)=2.0cm$ we have:

$x_{max}(t)=Ae^{-t/T}\\2.0cm=(7.0cm)e^{-7.6s/T}\\T=-\frac{7.6s}{ln(\frac{2.0cm}{7.0cm} )} \\T=6.07s$

For Part (b)

Apply $x_{max}(t)=Ae^{-t/T}$ with t=4.0s and T=6.07s we have

$x_{max}(t)=Ae^{-t/T}\\x_{max}(4.0s)=(7.0cm)e^{-4.0/6.07}\\x_{max|4.0s}=3.62cm$

8 0

4 years ago

Please I need your help

Alekssandra [29.7K]

17. 36mph 40 takeaway 6

4 0

3 years ago

Read 2 more answers

A 1250 kg car is stopped at a traffic light. A 3550 kg truck moving at 8.33 m/s strikes the car from behind, causing the bumpers

Minchanka [31]

A) Before the collision, the total momentum is

(1250 kg) (0 m/s) + (3550 kg) (8.33 m/s) ≈ 29,600 kg•m/s

B) Momentum is conserved, so after the collision it is still approximately 29,600 kg•m/s.

C) If v is the speed of the locked car-truck system, then

(1250 kg) (0 m/s) + (3550 kg) (8.33 m/s) = (1250 kg + 3550 kg) v

Solve for v :

29,571.5 kg•m/s = (4800 kg) v

v ≈ 6.16 m/s

5 0

2 years ago

In mammals, the weight of the heart is approximately 0.5% of the total body weight. Write a linear model that gives the heart we

hammer [34]

Answer:

1201 lbs

Explanation:

Given that in mammals, the weight of the heart is approximately 0.5% of the total body weight.

Let the weight of the heart of a mammal be H

And the weight of the total body be B

The linear model that can gives the heart weight in terms of the total body weight will be:

H = 0.005B

B.) To find the weight of the heart of a whale whose weight is 2.402 × 105 lbs, substitute the whole weight in the formula.

H = 0.005 × 2.402 × 10^5

H = 1201 lbs

Therefore, the weight of the heart of the whale is 1201 lbs

8 0

3 years ago

Two horses leave the starting gate at the beginning of a 2000 m long race. The brown horse has an acceleration of 2.2 m/s2 and a

forsale [732]

Define brown horse:
a₁ = 2.2 m/s², acceleration
v₁ = 18 m/s, top speed

Define the black horse:
a₂ = 1.7 m/s², accelerastopn
v₂ = 20 m/s, maximum speed

To travel 2000m, each horse accelerates to maximum speed, and cruises to the finish line.

For the brown horse:
The time to attain maximum speed is
t₁₁ = v₁/a₁ = 18/2.2 = 8.182 s
The distance travelled during the acceleration is
s = (1/2)*a*t² = 0.5*2.2*8.182² = 73.636 m
The time to travel the remaining distance is
t₁₂ = (2000 - 73.636)/18 = 107.02 s
The total time of travel is
t₁ = t₁₁ + t₁₂ = 8.182 + 107.02 = 115.2 s (approx)

For the black horse:
Time to attain maximum speed is
t₂₁ = 20/1.7 = 11.765 s
Distance traveled while accelerating is
0.5*(1.7 m/s²)*(11.765 s)² = 117.647 m
Time to travel the remaining distance is
t₂₂ = (2000 - 117.647)/20 = 94.118 s
The total time of travel is
t₂ = t₂₁ + t₂₂ = 11.765 + 94.118 = 105.9 s (approx)

Conclusion:
The black horse wins the race in about 106 s, while the brown horse takes about 115 s

Answer: The black horse wins.

8 0

4 years ago