<span>You are trying to find V2, the formula is V2</span>= <span><span>P1 / </span><span>P2 </span></span>⋅ V<span>1
</span><span>input your numbers, V2</span>= <span><span>90.0kPa / </span><span>20.0kPa </span></span>⋅ 4.0 L to get 18 L
Answer:
Following are the responses to this question:
Explanation:
They can measure the spontaneity of the reaction with the form,
Substituting the values of 
in the above expression information mostly on the playfulness of the reaction would be given to us from the expression above. This reaction is spontaneous if the price of 
is negative, and if it is positive the response is not random. At equilibrium, the values of 
are 0.
Answer:
becuase of the sun
in different places some places would be cold
Answer:
34.3 g
Explanation:
Step 1: Write the balanced equation
2 CH₃CH₂OH ⇒ CH₃CH₂OCH₂CH₃ + H₂O
Step 2: Calculate the moles corresponding to 50.0 g of CH₃CH₂OH
The molar mass of CH₃CH₂OH is 46.07 g/mol.
50.0 g × 1 mol/46.07 g = 1.09 mol
Step 3: Calculate the theoretical moles of CH₃CH₂OCH₂CH₃ produced
The molar ratio of CH₃CH₂OH to CH₃CH₂OCH₂CH₃ is 2:1. The moles of CH₃CH₂OCH₂CH₃ theoretically produced are 1/2 × 1.09 mol = 0.545 mol.
Step 4: Calculate the real moles of CH₃CH₂OCH₂CH₃ produced
The percent yield of the reaction is 85%.
0.545 mol × 85% = 0.463 mol
Step 5: Calculate the mass corresponding to 0.463 moles of CH₃CH₂OCH₂CH₃
The molar mass of CH₃CH₂OCH₂CH₃ is 74.12 g/mol.
0.463 mol × 74.12 g/mol = 34.3 g
