Answer:
COOHCOOH + 2OH⁻ ⇄ C₂O₄²⁻ + 2H₂O
Explanation:
The reaction of oxalic acid with a strong base like sodium hydroxide is the following:
COOHCOOH + OH⁻ ⇄ COOHCOO⁻ + H₂O (1)
In this first reaction, the oxalic acid loses one proton. In a second reaction with NaOH, the ion COOHCOO⁻ loses its second proton to form ion oxalate as follows:
COOHCOO⁻ + OH⁻ ⇄ C₂O₄²⁻ + H₂O (2)
The general reaction between oxalic acid and NaOH is (eq 1 + eq 2):
COOHCOOH + 2OH⁻ ⇄ C₂O₄²⁻ + 2H₂O
I hope it helps you!
Answer:
As explained
Explanation:
My reaction will be positive and I will feel elated that a new elements has been discovered as this will be a modification of the earlier claim by berzelius and the likes that there are over 106 known elements ; Metal, Non Metals and Metalloids.
However, fitting the new discovered element in between Tin and antimony may be an issue, as the physical properties of the new elements has to be known, its melting point, metals or non metals as this is paramount to be able to classify the elements. if the elements fits in between tin and antimony, it is an indication that the elements is mot likely a metal or non-mental and may belong to group IVB or VB. Another issue is, the discoverer will have to create his own periodic table to be able to stand in with the discovery of Dimitriy Mendelev.
Answer:
Ionic bonding is the complete transfer of valence electron(s) between atoms. It is a type of chemical bond that generates two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.
Explanation:
Answer:
Shift it toward the products
Explanation:
Imagine this equilibrium:
2A + B ⇄ A₂B
Let's think the expression for Kc:
Kc = [A₂B] / [A]² . [B]
Now, we have this situation:
2A ↑ + B ⇄ A₂B
As we are not in equilibrium, we have to think that Kc would decrease.
↓Kc = [A₂B] / [A]² ↑ . [B]
so we have to use Qc (reaction quotient). For this case
Qc < Kc, so the reaction → Product side
We have to make more product to counteract the reagent increase and thus return the system to equilibriumr
Answer: 6.77 x 1022 molecules of Cl2.
Explanation: First you need to write the correct BALANCED chemical reaction equation. Then you can determine how many moles of
C
l
2
would be produced from the available moles of Cl in 10.0g of
A
l
C
l
3
. Finally, you will convert this value into the number of molecules using Avogadro's number.
2
A
l
C
l
3
→
2
A
l
+
3
C
l
2
So, TWO moles of
A
l
C
l
3
will produce THREE moles of
C
l
2
.
The molecular weight of
A
l
C
l
3
is 133.33g/mol, so 10.0g is 10.0/133.33 = 0.075mol
With our equation ratio of 3/2 this will produce 0.1125 mol
C
l
2
.
0.1125 * 6.022 x
10
23
molecules/mole = 6.77 x
10
22
molecules of
C
l
2
