Question

An x-ray beam with wavelength 0.240 nmnm is directed at a crystal. As the angle of incidence increases, you observe the first strong interference maximum at an angle 66.0 ∘∘. What is the spacing ddd between the planes of the crystal?

Answer 1

Answer:

The spacing between the planes of the crystal is 0.295 nm

Explanation:

Given:

λ = wavelength = 0.24 nm

θ = angle of incidence = 66°

The spacing d between the planes of the crystal is equal:

$d=\frac{n\lambda }{2cos\theta } =\frac{1*0.24}{2*cos66} =0.295nm$