Answer:
Explanation:
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In this case, since the first law of thermodynamics allows us to understand how the energy behaves when heat and work are involved during a process, we can mathematically define it as:
Whereas Q is the heat added to the system, W the work done by the system and ΔU the change in the internal energy, we can notice that since 97.0 J of work are done on the system it would be negative and the given off heat is also heat due to the used convention; therefore the change in its internal energy turns out:
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Answer:
In order to answer the question, we convert the measurements given to a common base unit. For this case, we use seconds.
A) 0.02 seconds
B) 0.02 teraseconds x (10^12 s / 1 terasecond) = 2x10^10 seconds
C) 2,500 milliseconds x (1 s / 1000 ms) = 2.5 seconds
D) 25,000 nanoseconds x (1 x 10^-9 s / 1 nanosecond) = 2.5 x 10^-5 seconds
So ,The correct answer is option " D "
Solution: We are taking second element from the 4th period.
Element's name is Calcium.
It's symbol is Ca.
It is a metal because it looses its valence electron to form positive ions.
Calcium element lies in the second group of 4th period. The elements belonging to the second group are known as alkaline earth metals.
Atomic Number of Calcium = 20
Atomic number = Number of protons = Number of electrons
therefore,
Number of electrons and protons = 20
Atomic Mass of Calcium = 40
Atomic Mass = Number of neutrons + Number of proton
bu substituting the values of atomic mass and number of prtons, neutrons can be calculated
Number of neutrons = 20.
Answer:
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