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Lynna [10]
4 years ago
6

How many lenses does a microscope use?

Physics
2 answers:
Shalnov [3]4 years ago
7 0
The simplest optical microscope is the magnifying glass and is good to about ten times (10X) magnification. The compound microscope has two<span> systems of lenses for greater magnification, 1) the ocular, or eyepiece lens that one looks into and </span>2<span>) the objective lens, or the lens closest to the object.</span>
Nutka1998 [239]4 years ago
7 0
The simplest optical microscope has two lenses
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A 1.5kg cannon is loaded with a 0.52 kg ball . The cannon is ignited and launches the ball forward with speed of 75m/s. Determin
Mila [183]

Answer:

-26 m/s (backward)

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, the total momentum momentum of the cannon + ball system must be conserved before and after the explosion.

Before the explosion, they are both at rest, so the total momentum is zero:

p = 0

After the explosion, the total momentum is:

p=MV+mv

where

M = 1.5 kg is the mass of the cannon

m = 0.52 kg is the mass of the ball

v = +75 m/s is the velocity of the ball

V is the velocity of the cannon

Since the momentum is conserved, we can equate the two expressions:

0=MV+mv

And solving, we find V:

V=-\frac{mv}{M}=-\frac{(0.52)(+75)}{1.5}=-26 m/s

where the negative sign means the direction is opposite to that of the ball.

4 0
4 years ago
Describe how earth distance from the sun changes throughout the year when is earth closest to the sun
yaroslaw [1]
The father earth is away from the sun the more cold. 
The closer the sun gets the more hot.
When going threw these motions our seasons and days change as the earth moves around the sun while rotating. Hope this helped.

4 0
3 years ago
Two point charges totaling 8 μC exert a repulsive force of 0.15 N on one another when separated by 0.5 m. What is the charge on
nexus9112 [7]

Answer:

B. 7.4 x 10⁻⁶ C, 0.6 x 10⁻⁶ C

Explanation:

From Coulomb's Law the electrostatic repulsive force is given by the following formula:

F = kq₁q₂/r²

where,

F = Repulsive Force = 0.15 N

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

q₁ = Magnitude of 1st Charge = ?

q₂ = Magnitude of 2nd Charge = ?

r = Distance between Charges = 0.5 m

Therefore,

0.15 N = (9 x 10⁹ N.m²/C²)q₁q₂/(0.5 m)²

q₁q₂ = (0.15 N)(0.5 m)²/(9 x 10⁹ N.m²/C²)

q₁q₂ = 4.17 x 10⁻¹²

q₁ = (4.17 x 10⁻¹²)/q₂   -------------------- equation (1)

The sum of charges is given as:

q₁ + q₂ = 8 μC

q₁ + q₂ = 8 x 10⁻⁶

using equation (1):

(4.17 x 10⁻¹²)/q₂ + q₂ = 8 x 10⁻⁶

(4.17 x 10⁻¹²) + q₂² = 8 x 10⁻⁶ q₂

q₂² - (8 x 10⁻⁶) q₂ + (4.17 x 10⁻¹²) = 0

Solving this quadratic equation:

q₂ = 7.4 x 10⁻⁶ C   (OR)   q₂ = 0.56 x 10⁻⁶ C

q₂ = 7.4 μC   (OR)   q₂ = 0.6 μC

Therefore,

q₁ = (4.17 x 10⁻¹² C)/(7.4 x 10⁻⁶ C)

q₁ = 0.6μC

Now, if we solve with q₂ = 0.6 μC, we will get q₁ = 7.4 μC.

Therefore, the correct option will be:

<u>B. 7.4 x 10⁻⁶ C, 0.6 x 10⁻⁶ C</u>

8 0
3 years ago
How many elements did mendeleev place in group 2​
Pepsi [2]

Answer:5

Explanation:

8 0
3 years ago
An individual is nearsighted; his near point is 13.0 cm and his far point is 50.4 cm. what lens power is needed to correct his n
Colt1911 [192]

Answer:

= -1.984 Diopters

Explanation:

The lens should form an upright, virtual image at the far point.

Therefore;

The image distance, V will be -50.4 cm, since the image is virtual.

For objects at very far distant the object distance,u, will be ∞ ; This means that focal length, f, will be equivalent to image distance, v, that is -50.4 cm

Therefore; f = -50.4/100 = -0.504 m

But, since Power of a lens, P, is given by the reciprocal of focal length in meters, (1/f)

Then, power will be given by;

Power = 1/f

           = 1/-0.504 m

           =- 1.984

Power is measured in Diopters

Hence          <u>= -1.984 Diopters</u>

5 0
3 years ago
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