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eimsori [14]
2 years ago
5

Before a ball rolls down a hill, it has gravitational potential energy. Before a rubber ball bounces away from a surface, it has

elastic potential energy.
From the list below, select the type of potential energy that allows you to throw a ball.

A.
elastic potential energy
B.
chemical potential energy
C.
gravitational potential energy
D.
human potential energy
Physics
2 answers:
andrew11 [14]2 years ago
6 0

Answer:

chemical potential energy

Explanation:

study island

rjkz [21]2 years ago
5 0

Answer:

human potential energy

Explanation:

It is given that, before a ball rolls down a hill, it has gravitational potential energy.

Before a rubber ball bounces away from a surface, it has elastic potential energy.  

Human potential energy allows us to throw a ball. While throwing a ball, we have to apply some force by our muscles in order to done some work.Also, we know that the capacity to do work is called energy.

Hence, the correct option is (D) " human potential energy ".

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A light bulb dissipates 100 Watts of power when it is supplied a voltage of 220 volts.
ycow [4]

Given Information:

Power = P = 100 Watts

Voltage = V = 220 Volts

Required Information:

a) Current = I = ?

b) Resistance = R = ?

Answer:

a) Current = I = 0.4545 A

b) Resistance = R = 484 Ω

Explanation:

According to the Ohm’s law, the power dissipated in the light bulb is given by

P = VI

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and P is the power dissipated in the light bulb.

Re-arranging the above equation for current I yields,

I = \frac{P}{V}  \\\\I = \frac{100}{220} \\\\I = 0.4545 \: A \\\\

Therefore, 0.4545 A current is flowing through the light bulb.

According to the Ohm’s law, the voltage across the light bulb is given by

V = IR

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and R is the resistance of the light bulb.

Re-arranging the above equation for resistance R yields,

R = \frac{V}{I} \\\\R = \frac{220}{0.4545} \\\\R = 484 \: \Omega

Therefore, the resistance of the bulb is 484 Ω

3 0
3 years ago
Read 2 more answers
A 6.0 kg bucket of water is raised from a well by a rope. if the upward acceleration of the bucket is 3.9 m/s2, find the force e
shutvik [7]
I'm not good with math but I think it is 23.4
8 0
3 years ago
A ship sets sail from Rotterdam, The Netherlands, heading due north at 8.00 m/s relative to the water. The local ocean current i
Nuetrik [128]

Answer:

The velocity of the ship relative to the earth V = 9.05 \frac{m}{s}

Explanation:

The local ocean current is  = 1.52 m/s

Direction \theta = 40°

Velocity component in X - direction V_{x} = 1.52 \cos 40°

V_{x} = 1.164 \frac{m}{s}

Velocity component in Y - direction V_{y} = 8 + 1.52 \sin 40°

V_{y} = 8.97 \frac{m}{s}

The velocity of the ship relative to the earth

V = \sqrt{V_{x}^{2} + V_{y} ^{2}  }

Put the values of V_{x} and V_{y} we get,

⇒ V = \sqrt{1.164^{2} + 8.97 ^{2}  }

⇒ V = 9.05 \frac{m}{s}

This is the velocity of the ship relative to the earth.

7 0
3 years ago
Electric current flows through a long rod generating thermal energy at a uniform volumetric rate of
mario62 [17]
I don't know if you need to complete this question or do it otherwise, however, I managed to find on the Internet on several places this completion of your sentence:
<span>Electric current flows through a long rod generating thermal energy at a uniform volumetric rate of q = 2 x 10</span>⁶ W/m³. 
I'm not sure whether that is the answer you were looking for, but that's what I found.
5 0
3 years ago
Two 800 cm^3 containers hold identical amounts of a monatomic gas at 20°C. Container A is rigid. Container B has a 100 cm^2 pis
Vikki [24]

Answer:

1) Final Temperature of the gas in A will be GREATER than the temperature in B

2) Diagram of both processes on a single PV has been uploaded below

3) The Initial  pressures in containers A and B is 3039.87 J/liters

4) the final volume of container B is 923.36 cm³

Explanation:

Given that;

Temperature = 20°C = 293 K

mass of piston = 10 kg

Area = 100cm³

Volume V = 800 cm³ = 0.8 L

ideal gas constant R = 8.3 J/K·mol

1)

Final Temperature of the gas in A will b GREATER than the temperature in B

2)

Diagram of both processes on a single PV has been uploaded below,

3)

Initial  pressures in containers A and B

PV = nRT

P = RT/V

we substitute

P = (8.3 × 293) /  0.8

P = 2431.9 / 0.8

P = 3039.87 J/liters

Therefore, The Initial  pressures in containers A and B is 3039.87 J/liters

4)

Given that;

power = 25 W

time t = 15s

the final volume of container B = ?

we know that;

work done = power × time

work done = 25 × 15 = 375

Also work done = P( V₂ - V₁ )

so we substitute

375 = 3039.87 ( V₂ - 0.8 )

( V₂ - 0.8 ) = 375 / 3039.87

V₂ - 0.8 = 0.12336

V₂ = 0.12336 + 0.8

V₂ = 0.92336 Litres

V₂ = 923.36 cm³

Therefore, the final volume of container B is 923.36 cm³

7 0
3 years ago
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