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Andrej [43]
3 years ago
5

True or False: Conditions, like the number of times repeated, are used to end a [Repeat] block.

Engineering
1 answer:
Alja [10]3 years ago
4 0

Answer:

True. needa type in 20 more letters

Explanation:

ye.

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Consider an infinitely thin flat plate of chord c at an angle of attack α in a supersonic flow. The pressure on the upper and lo
amm1812

Answer:

X_cp = c/2

Explanation:

We are given;

Chord = c

Angle of attack = α

p u (s) = c 1

​p1(s)=c2,

and c2 > c1

First of all, we need to find the resultant normal force on the plate and the total moment about leading edge.

I've attached the solution

4 0
3 years ago
If gas costs $3.50 per gallon, how much would it cost to drive 500 miles in a city in a car that is 58.3 km/L
Akimi4 [234]
1 liter = .264 gallon
1 km = .621 mile

this means that 58.3km/L is equal to 137.13mpg

so

500/137.13 = 3.65 gallons of gas

3.65 x 3.5 = $12.78
5 0
3 years ago
The mean of hours that the average person watches television each day is 4.18 hours with a standard deviation of 1.19 hours. Fin
luda_lava [24]

Answer:

z = \frac{3-4.18}{1.19}=-0.992

z = \frac{5-4.18}{1.19}=0.689

And we can find this probability with this difference:

P(-0.992

And then we can conclude that the probability that someone watches between 3 and 5 hours a day is approximately 0.591 using a normal distribution

Explanation:

For this case we can define the random variable X as "hours that a person watches television". For this case we don't have the distribution for X but we have the following parameters:

\mu = 4.18,\sigma =1.19

We can assume that the distribution for X is normal

X \sim N(\mu = 4.18 , \sigma =1.19)

And we want to find this probability:

P(3

And we can use the z score formula given by:

z=\frac[X- \mu}{\sigma}

And we can find the z score for each limit and we got:

z = \frac{3-4.18}{1.19}=-0.992

z = \frac{5-4.18}{1.19}=0.689

And we can find this probability with this difference:

P(-0.992

And then we can conclude that the probability that someone watches between 3 and 5 hours a day is approximately 0.591 using a normal distribution

6 0
3 years ago
Consider a continuous-flow, indraft supersonic wind tunnel, which uses a vacuum pump to draw atmospheric air from outside of the
BigorU [14]
I believe it’s B but I’m not sure
3 0
3 years ago
A sedimentation basin in a water treatment plant has a length = 48 m, width = 12 m, and depth = 3 m. The flow rate = 4 m 3 /s; p
Slav-nsk [51]

Answer:

The minimum particle diameter that is removed at 85% is 1.474 * 10 ^⁻4 meters.

Solution

Given:

Length = 48 m

Width = 12 m

Depth = 3m

Flow rate = 4 m 3 /s

Water density = 10 3 kg/m 3

Dynamic viscosity = 1.30710 -3 N.sec/m

Now,

At the minimum particular diameter it is stated as follows:

The Reynolds number= 0.1

Thus,

0.1 =ρVTD/μ

VT = Dp² ( ρp- ρ) g/ 10μ²

Where

gn = The case/issue of sedimentation

VT = Terminal velocity

So,

0.1 = Dp³ ( ρp- ρ) g/ 10μ²

This becomes,

0.1 = 1000 * dp³ (1100-1000) g 0.1/ 10 *(1.307 * 10 ^⁻3)²

= 3.074 * 10 ^⁻6 = dp³ (.g01 * 10^6)

dp³=3.1343 * 10 ^⁻12

Dp minimum= 1.474 * 10 ^⁻4 meters.

8 0
3 years ago
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