Explanation:
Angular momentum is conserved.
I₁ ω₁ = I₂ ω₂
(½ Mr² + md²) ω₁ = (½ Mr²) ω₂
(½ (35 kg) (2.3 m)² + (84 kg) (2.3 m)²) (0.28 rev/s) = (½ (35 kg) (2.3 m)²) ω
ω = 1.624 rev/s
ω = 10.2 rad/s
Round as needed.
The normal force acting on the book by the inclined plane is most nearly 17N.
<h3>What is the normal force?</h3>
When a body is resting on the surface, the reaction force acting perpendicular to the surface of contact and in upward direction is equal to the the weight of the object.
On an inclined plane of 30 degree, a 2 kg block is resting. Its weight mg has two components, mgcos30 and mgsin30.
The Normal force will be equal to
N = mgcos30
N =2 x 9.81 x cos30
N = 17 Newtons
Thus, normal force acting on the book by the inclined plane is most nearly 17N.
Learn more about normal force.
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The so-called "velocity-time" graph is actually a "speed-time" graph. At any point
on it, the 'x'-coordinate is a time, and the 'y'-coordinate is the speed at that time.
'Velocity' is a speed AND a direction. Without a direction, you do not have a velocity,
and these graphs never show the direction of the motion. It seems to me that it would be
pretty tough to draw a graph that shows the direction of motion at every instant of time,
so my take is that you'll never see a true "velocity-time" graph.
At best, it would need a second line on it, whose 'y'-coordinate referred to a second
axis, calibrated in angle and representing the 'bearing' or 'heading' of the motion at
each instant. The graph of uniform circular motion, for example, would have a straight
horizontal line for speed, and a 'sawtooth' wave for direction.
Answer:
Electric Field Strength E₀ = E₀ = Constant
Explanation:
The Electric Filed Strength E₀ to an Infinite uniformly charge large sheet is constant how far is it i.e. it is independent of the distance away from the uniformly charge sheet.
Formula: E₀ = σ / 2 ε₀
Answer:
10m/s^2
Explanation:
Force = mass x acceleration
Acceleration = force/ mass
= 20000000/2000000
=10m/s^2
