The car is traveling at v=12m/s. Kinetic energy is given by this formula:
We can see that if the kinetic energy depends on the speed quadratically. This means that if you want to increase the kinetic energy x times you would have to increase speed
times. We conclude from this that car would have to go:
Take the upward and to-the-right directions to be positive (so down and to-the-left are negative).
The vertical forces acting on the object cancel, 6 N - 6 N = 0.
The horizontal forces exert a net force of 20 N - 3 N = 17 N. This net force is positive, so it points to the right. So the answer is A.
<u>Answer</u>:-
The main product is glucose despite as the matter of fact it produces several products such as:
•Oxygen
&
•Water too.
Explanation:
The reaction of photosynthesis is given below:
6CO2 + 12H2O + (in the presence of sunlight) → C6H12O6 + 6O2 + 6H2O
Carbon dioxide + Water + Sunlight → Glucose + Oxygen + Water.
<u>Inertia affects the motion of an object as follows:</u>
When an object is in motion, it will continue to be in the same state unless otherwise some outside force is being applied to it. Thus, inertia affects the motion of an object. It restricts some other force being acted upon the object.
But mass of an object is directly proportional to inertia. So when the inertia is more on an object, it means that the object has more mass. For example, if there are two similar bricks, one that is made up of mortar and the other one is made of Styrofoam.
To identify which brick is made of Styrofoam without lifting the bricks, push both the bricks with equal force, the one that has less resistance tends to move faster. This means that it has less inertia and hence less mass.
Answer:
The moment of inertia of large ring is 2MR².
(A) is correct option.
Explanation:
Given that,
Mass of ring = M
Radius of ring = R
Moment of inertia of a thin ring = MR²
Moment of inertia :
Moment of inertia is the product of the mass of the ring and square of radius of the ring.
We need to calculate the moment of inertia of large ring
Using formula of moment of inertia
Where, 
= moment of inertia at center of mass
M = mass of ring
R = radius of ring
Put the value into the formula
Hence, The moment of inertia of large ring is 2MR².
