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Diano4ka-milaya [45]
3 years ago
14

A fish-tank heater is rated at 96 W when connected to 120 V. The heating element is a coil of Nichrome wire. When uncoiled, the

wire has a total length of 4.2 m . What is the diameter of the wire?
Physics
1 answer:
nexus9112 [7]3 years ago
3 0

Answer:

0.232 mm.

Explanation:

Power, P = 96 W

Voltage, V = 120 V

Length of wire, l = 4.2 m

Let r be the radius of the wire.

Resistivity of nichrome, ρ = 1.5 x 10^-6 ohm metre

P = V^2 / R

R = 120 x 120 / 96 = 150 ohm

R = \rho \frac{l}{A}=\rho \frac{l}{\pi r^{2}}

r^2= \rho \frac{l}{\pi \times R}

r^2= \1.5\times10^{-6} \frac{4.2}{3.14 \times 150}

r = 1.16 x 10^-4 m

Diameter = 2 x r = 2 x 1.16 x 10^-4 = 2.32 x 10^-4 m = 0.232 mm

Thus, the diameter of the wire is 0.232 mm.

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Answer:

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Again item 2 refers to bonds between atoms and is eliminated.

This leaves only item 1.

Nuclear forces are very short range forces between components of the nucleus.

Weak nuclear forces are trillions of times smaller than strong forces.

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2 years ago
Coherent light of frequency 6.37×1014 Hz passes through two thin slits and falls on a screen 88.0 cm away. You observe that the
IgorC [24]

Answer:

The distance between the two slits is 40.11 μm.

Explanation:

Given that,

Frequency f= 6.37\times10^{14}\ Hz

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Position of the third order y =3.10 cm

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\lambda=\dfrac{c}{f}

where, c = speed of light

f = frequency

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}

\lambda=471\ nm

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m\times \lambda=d\sin\theta

d =\dfrac{m\times\lambda}{\sin\theta}

Where, m = number of fringe

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Here, \sin\theta =\dfrac{y}{l}

Put the value into the formula

d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}

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Hence, The distance between the two slits is 40.11 μm.

7 0
3 years ago
Why do the magnetic forces acting on the coil change as the current running through the coil changes?
VladimirAG [237]

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3 years ago
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julsineya [31]

Explanation:

The expression is :

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Using dimensional of A, B and C in above formula. So,

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Comparing the powers both sides,

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Now, solving equation (1) and (2) we get :

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