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3 years ago

In the electron cloud model of the atom,an orbital is defined as the most probable of what?

1 answer:

3 0

On orbital is where the electrons are located, and the last or outer orbital is where the valence electrons that determine the properties are located. <span />

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If a negatively charged ion is more concentrated outside the cell, the forces required to balance the chemical gradient would be

Lera25 [3.4K]

Outward, positively

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2 years ago

0.100 mol of CaCO3 and 0.100 mol CaO are placed in an 10.0 L evacuated container and heated to 385 K. When equilibrium is reache

HACTEHA [7]

Answer:

12.531 grams will be the final mass of calcium carbonate.

Explanation:

$CaCO_3(s)\rightleftharpoons CaO(s)+CO_2(g)$

Partial pressure of carbon dioxide gas at equilibrium = $P=0.220 atm$

Volume of carbon dioxide gas = V = 10.0 L

Moles of carbon dioxide gas formed = n

Temperature of the gas = T = 385 K

$PV=nRT$ ( ideal gas equation)

$n=\frac{PV}{RT}=\frac{0.220 atm\times 10.0 L}{0.0821 atm L/mol K\times 385 K}=0.06960 mol$

According to reaction , 1 mole of carbon dioxide gas is formed from 1 mole of calcium carbonate,0.06960 mole of carbon dioxide gas will be obtained from :

$\frac{1}{1}\times 0.06960 mol=0.06960 mol$ calcium carbonate

Moles of calcium carbonate at equilibrium = 0.100 mol - 0.06960 mol = 0.03040 mol

After addition of 0.300 atm of carbon dioxide gas, more amount of calcium carbonate will be be formed.

Here, at the same temperature, the equilibrium pressure of the carbon dioxide gas is 0.220 atm so, entire 0.300 atm of carbon dioxide will get convert to calcium carbonate.

So amount moles of carbon dioxide gas added = moles of calcium carbonate formed after re-establishment of an equilibrium :

Partial pressure of carbon dioxide gas added at equilibrium = $P=0.300 atm$

Volume of carbon dioxide gas = V = 10.0 L

Moles of carbon dioxide gas formed = n

Temperature of the gas = T = 385 K

$PV=nRT$ ( ideal gas equation)

$n=\frac{PV}{RT}=\frac{0.300 atm\times 10.0 L}{0.0821 atm L/mol K\times 385 K}=0.09491 mol$

Moles of calcium carbonate = 0.09491 mol

Total moles of calcium carbonate in the container :

=0.03040 mol + 0.09491 mol = 0.12531 mol

Mass of 0.12531 moles of calcium carbonate :

0.12531 mol × 100 g/mol = 12.531 g

12.531 grams will be the final mass of calcium carbonate.

4 0

3 years ago

2.How could you identify an element by its<br> number of protons?

kipiarov [429]

Answer:

The number of protons determines an element's atomic number (Z) and distinguishes one element from another. For example, carbon's atomic number (Z) is 6 because it has 6 protons. The number of neutrons can vary to produce isotopes, which are atoms of the same element that have different numbers of neutrons.

8 0

3 years ago

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What happens to the potassium atom when it reacts with the chlorine atom? What is the electron configuration of the potassium af

hodyreva [135]

Answer:

See explanation

Explanation:

Potassium is a metal. Remember that metals are electropositive in nature. This implies that they give out electrons when they undergo ionic bonding with nonmetals.

Chlorine is a nonmetal. So the bond between chlorine and potassium is ionic. Potassium gives out one electron to chlorine and the both ions now attain a stable octet.

The electronic configuration of potassium is [Ar]4s1. After giving out an electron to chlorine in an ionic bond, its electronic configuration is now [Ar].

3 0

3 years ago

A 50 g sample of an unknown metal is heated to 90.0C. It is placed in a perfectly insulated container along with 100 g of water

sergejj [24]

Q unknown = -Q H2O
Q H2O= (100g x 4.18 J/g C x (25C - 20C)
Q H2O = 2090J

-2090J = (50g x c x (25C-90C)
-2090J = -3250c
.64 = c

I am a high school student and have done this problem a few months ago for my test, hope this helps

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3 years ago

Read 2 more answers