Answer:
How many moles of Cl– ions are in 2.20 L of 1.50
Answer:

Explanation:
First you should calculate the volume of a big sphere,so:



Then you calculate the volume of a small spehre, so:



Finally you subtract the two quantities:


a process where the scientists performing the research influence the results, in order to show a certain result
D NACL because it is ionic bond and all the others are covalent
Answer:
V₂ = 18.13 L
Explanation:
Given data:
Mole of gas = 1 mol
Initial temperature = 273 K
Initial pressure = 1 atm
Final volume = ?
Final temperature = -41°C (-41+273 = 232 K)
Final pressure = 805 mmHg (805/760 = 1.05 atm)
Solution:
First of all we will calculate the initial volume of gas.
PV = nRT
V = nRT/P
V = 1 mol × 0.0821 mol.L/atm.K × 273 K / 1 atm
V = 22.4 L/atm / 1 atm
V = 22.4 L ( initial volume)
Now we will determine the final volume by using equation,
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Now we will put the values.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1 atm × 22.4 L × 232 K / 273 K × 1.05 atm
V₂ = 5196.8 atm .L. K / 286.65 atm.K
V₂ = 18.13 L