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STatiana [176]
4 years ago
14

An empty graduated cylinder has a mass of 11.4g.When it is filled with an unknown liquid to the 45.2 mL mark the cylinder and th

e liquid together weigh 95.1 gram. What is the density of the unknown liquid?
Chemistry
1 answer:
Lesechka [4]4 years ago
3 0
The density of the liquid is about 1.85 g/mL.

Density is mass/volume. The volume is given (45.2 mL). The mass must be found by subtracting the tare weight of the graduated cylinder from the total:
95.1 g- 11.4g = 83.7g

Using the mass and volume of the liquid, you can now calculate the density:
d = m/v = 83.7g/45.2 mL = 1.8517699115 g/mL.

Of the original values, the least number of significant figures are 3, so the answer must have a degree of accuracy of 3 significant figures:
1.8517699115 g/mL ≈ 1.85 g/mL.
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Answer:

How many moles of Cl– ions are in 2.20 L of 1.50

7 0
3 years ago
One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
PSYCHO15rus [73]

Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

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3 years ago
What is bias in an experiment?
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a process where the scientists performing the research influence the results, in order to show a certain result

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Which of the following has the greatest force between particles? Why?
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1.00 mole of an ideal gas at STP is cooled to -41°C while the
qwelly [4]

Answer:

V₂ = 18.13 L

Explanation:

Given data:

Mole of gas = 1 mol

Initial temperature = 273 K

Initial pressure = 1 atm

Final volume = ?

Final temperature = -41°C (-41+273 = 232 K)

Final pressure = 805 mmHg (805/760 = 1.05 atm)

Solution:

First of all we will calculate the initial volume of gas.

PV = nRT

V = nRT/P

V = 1 mol × 0.0821 mol.L/atm.K × 273 K / 1 atm

V = 22.4 L/atm / 1 atm

V = 22.4 L     ( initial volume)

Now we will determine the final volume by using equation,

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1 atm × 22.4 L ×  232 K / 273 K × 1.05 atm

V₂ = 5196.8 atm .L. K / 286.65 atm.K

V₂ = 18.13 L

5 0
3 years ago
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